Answer:
Yes, it is a function
Step-by-step explanation:
A function is a set of ordered pairs where there is no two of the same domain. The domain is the first coordinate which is x. In this case, the x coordinates are 4, 0, 11, 17. There is no two of the same domain so this is a function.
Hope This Helps :)
Answer:
Only equation 1 and 2 are equal.
Step-by-step explanation:
2 (x + 4)2 = 2
2( x² + 8x+ 16) = 2 Applying the square formula
2x² + 16x+ 32 = 2
2x² + 16x+ 32 -2= 0
2x² + 16x+ 30 = 0
2( x² + 8x+ 15)= 0 Taking 2 as common
x2 + 8x + 15 = 0------------eq 1
x2 + 8x + 15 = 0-------------eq 2
(x − 5)2 = 1
x²-10x+25= 1 Applying the square formula
x²-10x+25- 1= 0
x²-10x+24= 0-------------eq 3
x2 − 10x + 26 = 0 -------------eq 4
3(x − 1)2 + 5 = 0
3( x²-2x+1)+5= 0 Applying the square formula
3x²-6x+3+5= 0
3x²-6x+ 8= 0-------------eq 5
3x2 − 6x + 8 =1
3x2 − 6x + 8 -1=0
3x2 − 6x + 7 =0-------------eq 6
<h2>
Explanation:</h2>
Hello! Remember you have to write complete questions in order to get good and exact answers. Here I'll assume the graphed function comes from:
So this is the equation of a parabola that opens upward and whose vertex lies on the point:
The graph of this function is shown below. Which is true regarding the graphed function f(x)?
- It is true that the domain is the set of all real numbers because this is a polynomial function.
- It is true that the range is the set of all real numbers such that y ≥ 5
- It is true that this parabola opens upward
- It is true that it doesn't cut the x-axis
The answer for this problem i −10x2+66xy−36y2−5x+3y
Let's solve it by step by step.
(−5x+3y)(2x−12y+1)
=(−5x+3y)(2x+−12y+1)
=(−5x)(2x)+(−5x)(−12y)+(−5x)(1)+(3y)(2x)+(3y)(−12y)+(3y)(1)
=−10x2+60xy−5x+6xy−36y2+3y
So, -10x2+66xy-36y2-5x+3y
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