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nlexa [21]
3 years ago
13

Ryan wants to use the Fermi process to estimate the number of basketballs that would fill a gymnasium. As part of the process, h

e needs to estimate the volume of a basketball. The diameter of a basketball is about 10 in. 
Which estimate best approximates the volume of a basketball? 5×10^1 in³ 
5×10^2 in³
5×10^3 in³ 
5×10^4 in³
Mathematics
1 answer:
Westkost [7]3 years ago
3 0
A basketball is the shape of a sphere.

The volume of a sphere is given by

V= \frac{4}{3} \pi r^3

Given that the diameter of the basketball is 10 in., thus the radius is 10 / 2 = 5 in.

Thus, the volume of the basketball is given by

V= \frac{4}{3} \pi(5)^3 \\  \\ = \frac{4\times125}{3} \pi=523.6\ in^3

Therefore, The best approximate of the volume of the basketball is 5\times10^2\ in^3
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Given that g(x)=3x²-5x+7 find the following: <br> g(-x)
AURORKA [14]
G(x) = 3x² - 5x + 7
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(I will show you what I mean)

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is the same as
3x² - 5x + 7
by shifting the equation,

for example,
1 - 3 = -2
shifting other side
2 = -1 + 3

using 3x² - 5x + 7 to solve,

Solve\ using\ the\ formular\ \ \boxed{ x= { \frac{-b \pm \sqrt{b^2-4ac} }{2a} } }
a = 3
b = -5
c = 7
x= { \frac {-(-5) \pm \sqrt{ (-5)^2-4(3)(7) } }{2(3)} }
x= { \frac {5 \pm \sqrt{-59} }{6} }

∴This equation cannot be solved.
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