Given a right triangle with hypothenus of measure 34, the side opposite the angle θ of measure 30, and the side adjacent the angle theta of measure 16.
Let
x---------> the larger number
y---------> the smaller number
we know that
x+y=148------> equation 1
x=3y-2------> equation 2
substitute 2 in 1
[3y-2]+y=148--------> 4y=150---------> y=150/4------> y=37.5
x=3y-2----> x=3*37.5-2-----> x=110.5
the answer is
the larger number is 110.5
the smaller number is 37.5
This should have been worth more points, but anyways, here are the answers. Please give thanks :)
1.)Y = 5 - 3X<span>
2.) Y= </span><span>3X - 4</span><span>
3.) Y = 7 - X
4.) Y = -5X
5.) Y = </span>X +6 <span>
6.) Y = 5 -3X
7.) Y = 2 +</span>

<span>X
8.) </span>Y =

X - 3<span>
9.) Y= 2 - [</span>tex] \frac{2}{3} [/tex]<span>
10.) Y = 1 - 5X
11.) Y = 2 - </span>

<span>X
12.) Y = -5 -2X
13.) Y = X - 6
14.) Y = </span>

<span> -2X
15.) Y = 2 +</span>

<span>X
16.) Y = 2 +</span>

<span>X
17.) Y = 1 - 5X
18.) Y = </span>[<span>tex] \frac{3}{4} [/tex]</span>X + 2