The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Given the inequality:
3 ≤ |x + 2| ≤ 6
Hence:
x + 2 ≤ 6, -(x + 2) ≤ 6, 3 ≤ x + 2 and 3 ≤ -(x + 2)
This gives:
x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3
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1. incorrect
2. correct
3. incorrect (?)
The area of the triangle is 50in2, so she can create only 2 triangles.
Answer:
For every 5 campers there are 2 counselers
5a + 15 = 24b so,
10a + 30 = 48b,
sub to third equation,
10a + 30 + 35c = 49
10a + 35c = 19
perform elimination with second equation
10a + 45c = 21
10a + 35c = 19
________________-
10c = 2
c = 1/5
sub to second equation,
10a + (45)(1/5) = 21
10a + 9 = 21
10a = 12
a = 6/5
sub to first equation
(5)(6/5) - 24b = -15
6 + 15 = 24b
21 = 24b
b = 7/8
redo the calculations, correct me if I'm wrong
