Please help ASAP!!! At a dinner party, two desserts are being served. Six of the guests choose cheesecake, and eight of the gues
1 answer:
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The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now,
We know that the sum of probability of an event and its complement is 1.
So,
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.
Answer: Our required probability is 0.3387.
Step-by-step explanation:
Since we have given that
Number of red cards = 4
Number of black cards = 5
Number of cards drawn = 5
We need to find the probability of getting exactly three black cards.
Probability of getting a black card =
Probability of getting a red card =
So, using "Binomial distribution", let X be the number of black cards:
Hence, our required probability is 0.3387.