2 answers:
Answer:
1,=(6x-8)(x+1)
=6x²+6x-8x-8
=6x²-2x-8
2,=(6x+8)(x-1)
=6x²-6x+8x-8
=6x²+2x-8
3,=(6x+1)(x-8)
=6x²-42x+x-8
=6x²-41x-8
Answer:
second option
Step-by-step explanation:
Expand the factors using FOIL
1
(6x - 8)(x + 1) = 0
6x² - 2x - 8 = 0 ≠ 6x² + 2x - 8
2
(6x + 8)(x - 1) = 0
6x² + 2x - 8 = 0 ← True
3
(6x + 1)(x - 8)
= 6x² - 47x - 8 = 0 ≠ 6x² + 2x - 8 = 0
Thus the factored form is
6x² + 2x - 8 = 0
(6x + 8)(x - 1) = 0 → second option
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