Hey mate,
We have,
st²-pqr
Given values,
p= -2,q=5,r= -7,s=0 and t=4
On substituting,we obtain:
→(0)(4)²-(-2)(5)(-7)
→16-(70)
→16-70
<u>→</u><u>-</u><u>5</u><u>4</u>
It's 64 good luck with the answer
Any number to the power of zero is one. Think of it like this - a power is basically multiplying a certain number of the same integer together. So, if we multiply 0 fours together, we just get 1. Alternatively, consider it like this - 4 to the power of one divided by four to the power of one is equal to four to the power of zero, so 4/4=1 is 4 to the power of zero. Therefore, 4^0 is 1.
According to my calculations the answer is 13/25 hope this helps