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2 years ago

Step-by-step to reduce the radical of the square root Of 160

Mathematics

2 answers:

notka56 [123]2 years ago

8 0

Answer:

$4\sqrt{10}$

Step-by-step explanation:

$\sqrt{160}$

$\sqrt{16 * 10}$

$4\sqrt{10}$

because 16 is a perfect square root and it splits into 4 * 4 while 10 isnt a perfect square root so it stays inside.

lisabon 2012 [21]2 years ago

3 0

Answer:

4 $\sqrt{10}\\$

Step-by-step explanation:

To reduce a radical of a square root, you want to find a perfect square that multiplies into that number. 16 is a perfect square (of 4) and can be divided into 160. so $\sqrt{160\\}$ becomes $\sqrt{16}$ x $\sqrt{10}$ (because 16 x 10 = 160) then we simplify the square root of 16 to be 4. We leave the square root of 10 because it cannot be simplified.

Hope this helps!

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A student needs to make a square cardboard piece. The cardboard should have a perimeter equal to at least 92 inches. The functio

Illusion [34]

Answer:

$s\geq 23$

Step-by-step explanation:

We are given that a student needs to make a square cardboard piece.

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3 years ago

The length of a rectangle is 4 more than 3 times the width if the perimeter of the rectangle is 18.4 cm what is the area of the

garik1379 [7]

Let's call the width: w

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and the parameter would be 2(w+3w+4), that is 2*(4w+4), that is 8w+8.

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8w+8=18.4
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this is the width, and the lenght is:
4+3*1,3=4+3.9=7.9

and the area is their product:
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3 years ago

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Vinvika [58]

Answer:

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Step-by-step explanation:

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Answer:

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