2 years ago

Step-by-step to reduce the radical of the square root Of 160

Mathematics

2 answers:

notka56 [123]2 years ago

8 0

Answer:

$4\sqrt{10}$

Step-by-step explanation:

$\sqrt{160}$

$\sqrt{16 * 10}$

$4\sqrt{10}$

because 16 is a perfect square root and it splits into 4 * 4 while 10 isnt a perfect square root so it stays inside.

lisabon 2012 [21]2 years ago

3 0

Answer:

4 $\sqrt{10}\\$

Step-by-step explanation:

To reduce a radical of a square root, you want to find a perfect square that multiplies into that number. 16 is a perfect square (of 4) and can be divided into 160. so $\sqrt{160\\}$ becomes $\sqrt{16}$ x $\sqrt{10}$ (because 16 x 10 = 160) then we simplify the square root of 16 to be 4. We leave the square root of 10 because it cannot be simplified.