No bc the square root of 75 is 8 and some change and that times 4 ( which is how you get the perimeter ) is 34 and some change. So he’ll need at LEAST 35 feet just for the perimeter
since it has a diameter of 28, then its radius must be half that or 14.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=14 \end{cases}\implies A=\pi (14)^2\implies A=196\pi ~\hfill \stackrel{\stackrel{semi-circle}{half~that}}{98\pi }](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D14%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2814%29%5E2%5Cimplies%20A%3D196%5Cpi%20~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7Bsemi-circle%7D%7Bhalf~that%7D%7D%7B98%5Cpi%20%7D)
First what you wanna do is get y by it’s self. To do that is to first add 5 on each side.
-5+3y=-4
+5 +5
3y= 1
Than you divide 3 on each side and it would give you y=1/3 if it’s a fractions problem but if you looking for decimals you would have to divide 1 by 3 which gets you .33333333.
OPTION A ,C AND E IS CORRECT
1/10 x 50,000 = 5,000
100 x 50 =5,000
10 x 500 = 5,000