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Studentka2010 [4]
3 years ago
7

The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c =

5. The discriminate b2 – 4ac is 41. Now, complete step 5 to solve for the zeros of the quadratic function. 5. Solve using the quadratic formula. x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction What are the zeros of the function f(x) = x + 5 – 2x2? x = StartFraction negative 1 plus or minus StartRoot 41 EndRoot Over negative 4 EndFraction x = StartFraction 1 plus or minus StartRoot 41 EndRoot Over negative 4 EndFraction x = StartFraction negative 1 plus or minus StartRoot 39 EndRoot Over negative 4 EndFraction x = StartFraction 1 plus or minus StartRoot 39 EndRoot Over negative 4 EndFraction
Mathematics
2 answers:
joja [24]3 years ago
7 0

Answer:

The CORRECT answer is A.

Step-by-step explanation:

just did it.

maw [93]3 years ago
4 0

Answer:

To solve for the zeros of the function equate f(x) = 0

That's

- 2x² + x + 5 = 0

Using the quadratic formula

x =  \frac{ - b± \sqrt{ {b}^{2}  - 4ac} }{2a}

a = - 2 b = 1 c = 5

And from the question

b² - 4ac = 41

So we have

x =  \frac{ -  1±  \sqrt{41} }{2( - 2)}  =  \frac{ - 1± \sqrt{41} }{ - 4}

x =  \frac{1± \sqrt{41} }{4}

We have the final answer as

x =  \frac{1   + \sqrt{41} }{4}  \:  \:  \:  \: or \:  \:  \:  \: x =  \frac{1 -  \sqrt{41} }{4}

Hope this helps you

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