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OleMash [197]
3 years ago
12

Convert 9/20 to a decimal

Mathematics
2 answers:
topjm [15]3 years ago
8 0

Answer:

0.45

Step-by-step explanation:

Andrej [43]3 years ago
5 0
0.45 just divide 9 by 20 to get it into decimal form
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Determine if 0.949449444944449444449 rational or irrational and give a reason for answer. ​
Kamila [148]

Answer:

irrational if it's more after this number but if it stops at the last 9 then it's a rational number

hope this helps

have a good day :)

Step-by-step explanation:

4 0
3 years ago
A running coach checks on his team's best recorded sprinting times during practice. Drag the runners in order from the greatest
horrorfan [7]

Carla

Amir

Carlo

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From greatest to least!

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3 years ago
Geraldo has a coupon for $12 off the total bill at a local restaurant. Geraldo does not want to spend more than $65. The inequal
Trava [24]
In here, we could write an equality as x – 12 < 65. In solving inequalities, we follow the same rule as solving algebraic expressions. We will transpose 12 to the other side, giving us x < 65 + 12. Simplifying, we have x < 77. Geraldo must have a bill less than $77 in order for him not to spend more than $65.
3 0
3 years ago
Read 2 more answers
How do you write 1/30 in decimal form?
Anarel [89]
Converting the fraction 1/30 into a decimal is very easy. 

To get 1/30 converted to decimal, you simply divide 1 by 30.
1/30 as a decimal is:

<span>0.033333333</span>
8 0
3 years ago
20 points if you help me solved this problem plz it’s urgent someone plz help me I need help! Will mark you as brainiest!
deff fn [24]

Answer:  see below

<u>Step-by-step explanation:</u>

C(x) = 39 when 0 < x ≤ 1.0

C(x) = 63 when 1.0 < x ≤ 2.0

C(x) = 87 when 2.0 < x ≤ 3.0

C(x) = 111 when 3.0 < x ≤ 4.0

C(x) = 135 when 4.0 < x ≤ 5.0

C(x) = 159 when 5.0 < x ≤ 6.0

Based on the information I provided above, the answers are:

a) x= 0.6, C(x) = 1.0

   x = 1.0, C(x) = 39

   x = 1.1,  C(x) = 63

   x = 2.5, C(x) = 87

   x = 3.0, C(x) = 87

   x = 4.8, C(x) = 135

   x = 5.0, C(x) = 135

   x = 5.3, C(x) = 159

b) If C(x) = 87, then 2.0 < x ≤ 3.0

c) Domain (all possible x-values): 0 < x ≤ 6.0

d) Range (all possible y-values): {39, 63, 87, 111, 135, 159}

3 0
3 years ago
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