Every rational number has a base-2 representation, but only the ones with denominators that are powers of 2 will require a finite number of bits to fully represent it.
For example,
whereas a number whose denominator contains anything else like 1/3 will need an infinite number of bits to represent it exactly.
and so on, so that it has a repeating but non-terminating base-2 representation
Answer:
isosceles
Step-by-step explanation:
two sides equal
M=43-6
m=37 thats your answer
Step-1 : Multiply the coefficient of the first term by the constant 6 • -10 = -60
Step-2 : Find two factors of -60 whose sum equals the coefficient of the middle term, which is -11 .
-60 + 1 = -59
-30 + 2 = -28
-20 + 3 = -17
-15 + 4 = -11 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -15 and 4
6n2 - 15n + 4n - 10
Step-4 : Add up the first 2 terms, pulling out like factors :
3n • (2n-5)
Add up the last 2 terms, pulling out common factors :
2 • (2n-5)
Step-5 : Add up the four terms of step 4 :
(3n+2) • (2n-5)
Which is the desired factorization
Final result :
(2n - 5) • (3n + 2)
