Answer:
197
Step-by-step explanation:
You have 6 sides of this object. So we will calculate six surface areas.
P1=5x5=25 ( on the top)
P2=9x5=45 ( on the bottom)
P3= 5x5= 25 (left side)
P4=6,4x5=32 (rightside)
P5= (9+5)x5/2=70/2=35 ( front trapeze)
P6=P5=35 ( behided trapeze)
P= p1+p2+p3+p4+p5+p6=
25+45+25+32+35+35 =197
The perimeter of the a and BC is 14 unitsBecause if you add all of the sides together you get 14 and I need points
Answer:
-9/4
Step-by-step explanation:
putting these to y/x form it is 9/-10 and -9/-6 which has a difference of -9/4 (hopefully this is correct-)
2[4 − 7(3x + 4y)] + 2[3x(−2y)]
2[4 - 21x -28y] + 2[-6xy]
8 - 42x - 56y -12xy
the perimeter of given rectangular garden is (8 - 42x - 56y -12xy).
y = -1/2x + 5 should be your equation because it is 5 ft above sea level and its eroding, or going down, 1 ft per 20 years. So every year, the sand dune erodes 1/20 ft more.
Hope this helps!
