Answer: 294√3
Explanation:
1) The described hexagon has these featrues:
a) 6 congruent equilateral triangles whose side lengths measure 14
b) height of each triangle = apotema = a
c) the area of each triangle is base × a / 2 = 14 × a / 2 = 7a
2) a is one leg of a right triangle whose other leg is 14 / 2 = 7, and the hypotenuse is 14.
3) Then you can use Pythagorean theorem fo find a:
14² = 7² + a² ⇒ a² = 14² - 7² = 147 ⇒ a = √ 147 = 7√3
4) Therefore, the area of one triangle is: 14 × 7√3 / 2 = 49√3
5) And the area of the hexagon is 6 times that: 6 × 49√3 = 294√3
A.50*9.8
B.50*1.6
C.45.359237
D.45.3*1.6
Na bro i dont even know what’s that tbh
Answer:
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Answer:
k = 11b - 8 (easiest to understand)
extra:
k = -8 + 11b
or
11b = -8 - k
etc. ( anything mixing up the components of the equation ).
