3 years ago

Find the slope of the line passing through the points (-4,8) (-8,3)

1 answer:

3 0

$m=\dfrac{y_2-y_1}{x_2-x_1}\\\\
m=\dfrac{8-3}{-4-(-8)}\\
m=\dfrac{5}{4}$

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grandymaker [24]

I think your answer is 56

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Elodia [21]

I believe its B but I'm not completely sure

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Vera_Pavlovna [14]

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4 years ago

slava [35]

Answer:

Yes, $s = -4$ is a solution to $- 2 \geqslant s$

This is because $- 2 > - 4$ .

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3 years ago

postnew [5]

For this case we have:

Let a function of the form $y = f (x)$

By definition, to graph $y = f (x + h)$ , where $h> 0$ , we must move the graph of f (x), h units to the left.

We observe that the red graph has the same form as the black graph, but it is displaced "h" units to the left.

It is observed that $h = 3$

So, if the black graph is given by $y = f (x)$ , the red graph is given by: $y = f (x + 3)$

Answer:

$y = f (x + 3)$

Option A

3 0

3 years ago