The vertex of any equation in the form y = a(x-b)^2 + c is (b,c). Keeping that in mind, we figure out that:
The first one is (-9,-5)
The second one is (-5,-6)
The third one is (5,6)
The fourth one is (6,9)
The fifth one is (5,-9)
I think your answer would be D-12
C. Fernando incorrectly found the product of -2 and -5
<span>(should be +10 instead of -10)</span>
X = 2V6 + 4 or x =-2V6 + 4
