Well the answer is going to be 8 1/4.
hope that helped
Answer:
G
Step-by-step explanation:
Hope this helps
Answer:
0.2 or 20%
Step-by-step explanation:
If the times of arrival vary uniformly, there is an equal chance of an employee reporting at any given time between 8:40 and 9:30.
The range between 8:40 and 9:30 is 50 minutes.
The range between 9:00 and 9:10 is 10 minutes.
Therefore, the probability that a randomly chosen employee reports to work between 9:00 and 9:10 is:

The probability is 0.2 or 20%.
Answer:
Step-by-step explanation:
Information given
n=370 represent the sample selected
estimated proportion of readers owned a laptop
is the value that we want to test
z would represent the statistic
represent the p value
Creating the hypothesis
We need to conduct a hypothesis in order to test if the true proportion of readers owned a laptop is different from 0.45, the system of hypothesis are:
Null hypothesis:
Alternative hypothesis:
The statistic is:
(1)
Replacing we got:
Calculating the p value
We have a bilateral test so then the p value would be:
Answer:
C
Step-by-step explanation:
<u>Equation A</u>
16x - 7 = 11x - 32
(16x - 7) - 11x = (11x - 32) -11x
5x - 7 = -32
(5x - 7) + 7 = (-32) + 7
5x = -25
(5x)/5 = (-25)/5
x = -5
<u>Equation B</u>
-4x - 10 = 2x + 20
(-4x - 10) - 2x = (2x + 20) - 2x
-6x - 10 = 20
(-6x - 10) + 10 = (20) + 10
-6x = 30
(-6x)/-6 = (30)/-6
x = -5
Both Equation A and Equation B have a solution of -5.