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julia-pushkina [17]
3 years ago
6

If you are told that opposite sides of this quadrilateral are parallel and that the measure of angle A is 105°, can you tell the

measure of angle B? If so, give the measure, and if not, answer no.

Mathematics
1 answer:
iVinArrow [24]3 years ago
5 0

Answer:

its all smth if its a 150 all the side smtg

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jann designs a new logo for kim's website. kim pays jan $45 for 5 hours of work. How much money does kim pay jan per hour?
Amanda [17]
Jann pays Kim $9 an hour
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F m∠A = 110 degrees and m∠B = 35 degrees, find m∠1.
NISA [10]
I think M<1 will equal 35 degrees.
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Hiiioo! Hope everyone is having a good day! Can someone please help with this!❤️❤️❤️❤️:D
My name is Ann [436]

Answer:

AA

Step-by-step explanation:

6 0
3 years ago
A rocket is fired with an initial vertical velocity of 40 m/s from a launch pad 45 m high, and its height is given by the formul
N76 [4]

Answer:

1) 125 meters

2) For 9 seconds.

Step-by-step explanation:

The rocket's height is given by the formula -5t^2+40t+45.

Notice that this is a quadratic.

Part 1)

Since this is a quadratic, the highest height the rocket goes will be the vertex of our quadratic. Remember that the vertex of a quadratic in standard form is:

(-\frac{b}{2a}, f(-\frac{b}{2a}))

So, let's identify our coefficients. The standard quadratic form is:

ax^2+bx+c

Therefore, in this case, our a is -5, b is 40, and c is 45.

So, let's find the x-coordinate of our vertex. Substitute 40 for b and -5 for a. This yields:

x=\frac{-(40)}{2(-5)}

Multiply and reduce. So:

x=-40/-10=4

Now, substitute 4 for t to find the height. So:

-5(4)^2+40(4)+45

Evaluate:

=-5(16)+40(4)+45

Multiply and add:

=-80+160+45=125\text{ meters}

Therefore, the highest the rocket goes up is 125 meters.

Part 2)

To find out for how much time the rocket is in the air, we can think about after how many seconds after launch will the rocket land.

If the rocket lands, the height h will be 0. So, we can set our expression equal to 0 and solve for t:

-5t^2+40t+45=0

First, let's divide everything by -5. This yields:

t^2-8t-9=0

We can factor:

(t+1)(t-9)=0

Zero Product Property:

t+1=0\text{ or } t-9=0

Solve for t:

t=-1\text{ or } t=9

In this case, since t is our time in seconds, -1 seconds does not make sense. So, we can remove -1 from our solution set.

Therefore, 9 seconds after launch, the rocket will touch the ground.

Therefore, the rocket was in the air for 9 seconds.

And we're done!

6 0
3 years ago
A line passes through the points (–1, –5) and (4, 5). The point (a, 1) is also on the line.
IgorC [24]

Answer:

a = 2

Step-by-step explanation:

Let's find the equation of the line using the 2 points given.

Let's call -1 as x_1 and -5 as y_1

also, 4 as x_2 and 5 as y_2

The equation of line is :

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

<em>Let's plug the points and get the equation of the line:</em>

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Now, to find a, we substitute a in x and 1 in y of the equation of the line we just got:

y=2x-3\\1=2(a)-3\\1=2a-3\\2a=4\\a=\frac{4}{2}=2

4 0
3 years ago
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