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bearhunter [10]
4 years ago
6

The histogram shows the weekly rates charged by different daycares for a 2-year-old child.

Mathematics
1 answer:
serious [3.7K]4 years ago
8 0

Answer: the answer in c on edge

Step-by-step explanation:

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<u>gusuhuysh7zywjis</u><u> </u><u>uh</u><u> </u><u>sksisyysishs</u>

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At a school fair you have a choice of randomly picking a ball from Basket A or Basket B. Basket A has 5 green balls, 3 red balls
Karolina [17]
Basket A is 3/16 red.
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The answer is Basket B.
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3 years ago
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PLS HELP ME ASAP WITH THIS WHOLE PAGE! THANK YOU SOO MUCH!!
Doss [256]
1a) The function has arrows on both ends and no place in the middle where it is not defined. Its domain is ...
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1b) The function gives no output values below -3, but it gives output values of -3 and all above that. Its range is ...
  y ≥ -3

1c) For values of x less than -1, the function's output is 1. This matches g(x) and s(x). At x=0, the function's output is -3, which only matches g(x). The appropriate choice is ...
  g(x)


2b) The function is only defined for 0 ≤ x < 8. This is its domain.

3) A definition might be ...
y=\left\{ \begin{array}{rcl}x+1 & \mbox{for} & -4\le x \le 1\\-x & \mbox{for} & 1 < x \le 3 \end{array}

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3 years ago
1.64 written as fraction in simplest form
erastovalidia [21]
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8 0
3 years ago
84. Use properties of exponents to rewrite each expression with only positive, rational exponents. Then find the numerical value
Yakvenalex [24]

Answer:

a) 1/27

b) 16

c) 1/8

Step-by-step explanation:

a) x^{-3/2}

One of the properties of the exponents tells us that when we have a negative exponent we can express it in terms of its positive exponent by turning it into the denominator (and changing its sign), so we would have:

x^{-3/2}=\frac{1}{x^{3/2} }

And now, solving for x = 9 we have:

\frac{1}{x^{3/2}}=\frac{1}{9^{3/2} }  =\frac{1}{27}

b) y^{4/3}

This is already a positive rational exponent so we are just going to substitute the value of y = 8 into the expression

y^{4/3}=8^{4/3}=16

c) z^{-3/4}

Using the same property we used in a) we have:

z^{-3/4}=\frac{1}{z^{3/4} }

And now, solving for z = 16 we have:

\frac{1}{z^3/4} } =\frac{1}{16^{3/4} } =\frac{1}{8}

4 0
3 years ago
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