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2 years ago

Eli Whitney invented the the cotten gin

Mathematics

2 answers:

gtnhenbr [62]2 years ago

6 0

He did. Are you asking to make sure?

alekssr [168]2 years ago

4 0

The answer is True.

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Find an equation of the circle that has center (1, -1) and passes through (5, -6).

Sloan [31]

Answer:

Step-by-step explanation:

(x-1)²+(y+1)²=41

6 0

3 years ago

You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

6 0

2 years ago

Use the drawing tools to form the correct answers on the grid.

Dafna1 [17]

Answer:

I don't understand the array of numbers as written in the question.

Step-by-step explanation:

See attached image

5 0

1 year ago

Please help me this is due tomorrow thank you

marusya05 [52]

Answer:

The answer is option B.

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

50 POINTS What are the values of a1 and r of the geometric series? 2 – 2 + 2 – 2 + 2

torisob [31]

Answer:

a1=2 and r=-1

Explanation:

"A geometric series is a series with a constant ratio between successive terms".

Here, we can observe that the first term 'a' is '2'.

And the common ratio 'r' =

Therefore, the first term 'a' is 2 and common ratio 'r' is '-1'.

8 0

3 years ago

Read 2 more answers