Answer:
Step-by-step explanation:
Start by finding how many integers there are from 10-30...
30-10+1=20+1=21
Note we have to add 1 since it is inclusive.
Now, let's find how many multiples of 4 or 5 there are from 10-30...
4*3=12
4*4=16
4*5=20
4*6=24
4*7=28
5*2=10
5*3=15
5*4=20
5*5=25
5*6=30
5+5-1=9
Note we have to subtract 1 since 20 is counted twice.
The probability would be...
Hello! :)
543,982 rounded to the nearest hundred thousand would be 500,000. Because the digit 4 is less than 5, it would be 600,000. If the digit where the 4 is was 5 or more, it would round to 600,000,
543,982 to the nearest hundred is 500,000.
Hope this helped you!
THEDIPER
Answer:
-18
Step-by-step explanation:
cus the line is going down
The three consecutive integers are: x, (x+1) and (x+2).
We can suggest this equation:
x+(x+1)+(x+2)=126
3x+3=126
3x=126-3
3x=123
x=123/3
x=41
x=41
(x+1)=41+1=42
(x+2)=41+2=43
Answer: the three consecutive integers would be: 41,42 and 43.
Answer:
B
Step-by-step explanation:
