Answer:
The total blood given is 5.5 liters
Thus, total alcohol needed for BAC (blood alcohol content) to exceed 0.1 gram per 100 ml will be 0.1/100 × 5500 = 5.5 grams alcohol.
1 oz = 28.3 grams
28.3 gram water = 28.3 ml
It has 20 percent alcohol by volume,
Therefore, alcohol in one drink will be:
20/100 × 28.3
= 5.66 ml
= 5.66 × 0.79 (density of ethanol)
= 4.47 gram
Thus, no of drinks will be 5.5 g / 4.47 g = 1.2
Hence, 1.2 drinks will make the BAC to exceed 0.1 g / 100 ml in the blood.
