So to do this you have to first calculate the sum subtract, multiply both sides by 10, move the terms, and collect like terms. So X=3460 I believe
Your welcome
Answer:
40%
Step-by-step explanation:
Discount price = 22 - 13.20 = $8.80
Discount percentage = 
= 40%
The first term is -16, so we have
... a[1] = -16
Each term is -1/4 of the one before it, so the recursive rule is
... a[n+1] = (-1/4)a[n]
It depends on what the figure looks like. You could have SSS is If three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent. As you can see, the SSS Postulate does not concern itself with angles at all.
SAS is have two triangles where we know two angles and the included side are equal.
ASA If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent
Idk what the figures you are talking about but I gave u some for triangles. If you comment back I can help u if you give me the figures you are talking about
So if it wants to know which fraction is greater, your going to need to find a common denominator (the bottom number)
7/12 & 5/6 6 and 12 have a least common multiple (LCM) of 12... this means that both six and 12 can go into twelve. now you convert the fraction's numerator so it equals everything correctly. Now, since 7/12 already has a denominator of twelve than that means that you dont need to change it. but with 5/6 you need to multiply it by 2. (since 6x2=12)
so now it is 10/12 & 7/12. which one now has the bigger numerator?
A:10/12 > 7/12
for adding the two fractions, you also convert the denominator so it equals 10/12 and 7/12 then just add the numerator
A: 17/12(this is in improper form) so now it's 1 5/12
do the same thing with subtracting but then subract instead of add (obviously)
A: 10/12-7/12= 3/12 which can be simplified into 1/4
when multiplying a fraction, you don't need to change anything, just multiply right across, so 7x5=35 and 12x6=72
A: 35/72
Now try the other one on your own using the instructions i gave you!
Hope this helps!
