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3 years ago

What is the equation of a line that has a slope of 3 and a y-intercept of -3

Mathematics

2 answers:

LenKa [72]3 years ago

7 0

Answer:

y = 3x-3

Step-by-step explanation:

y = mx+b

m is your slope and b is your y-intercept

plug those numbers in

y = 3x-3

LUCKY_DIMON [66]3 years ago

6 0

The slope-intercept form:

y = mx + b

m - slope

b - y-intercept

We have m = 3 and b = -3. Substitute:

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Is anybody else here to help me ??

Akimi4 [234]

Answer:

$\cot(x)+\cot(\frac{\pi}{2}-x)$

$\cot(x)+\tan(x)$

$\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}$

$\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}]$

$\csc(x)[\frac{1}{\cos(x)}]$

$\csc(x)[\sec(x)]$

$\csc(x)[\csc(\frac{\pi}{2}-x)]$

$\csc(x)\csc(\frac{\pi}{2}-x)$

Step-by-step explanation:

I'm going to use $x$ instead of $\theta$ because it is less characters for me to type.

I'm going to start with the left hand side and see if I can turn it into the right hand side.

$\cot(x)+\cot(\frac{\pi}{2}-x)$

I'm going to use a cofunction identity for the 2nd term.

This is the identity: $\tan(x)=\cot(\frac{\pi}{2}-x)$ I'm going to use there.

$\cot(x)+\tan(x)$

I'm going to rewrite this in terms of $\sin(x)$ and $\cos(x)$ because I prefer to work in those terms. My objective here is to some how write this sum as a product.

I'm going to first use these quotient identities: $\frac{\cos(x)}{\sin(x)}=\cot(x)$ and $\frac{\sin(x)}{\cos(x)}=\tan(x)$

So we have:

$\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}$

I'm going to factor out $\frac{1}{\sin(x)}$ because if I do that I will have the $\csc(x)$ factor I see on the right by the reciprocal identity:

$\csc(x)=\frac{1}{\sin(x)}$

$\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

Now I need to somehow show right right factor of this is equal to the right factor of the right hand side.

That is, I need to show $\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}$ is equal to $\csc(\frac{\pi}{2}-x)$ .

So since I want one term I'm going to write as a single fraction first:

$\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)}$

Find a common denominator which is $\cos(x)$ :

$\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}$

$\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}$

$\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}$

By the Pythagorean Identity $\cos^2(x)+\sin^2(x)=1$ I can rewrite the top as 1:

$\frac{1}{\cos(x)}$

By the quotient identity $\sec(x)=\frac{1}{\cos(x)}$ , I can rewrite this as:

$\sec(x)$

By the cofunction identity $\sec(x)=\csc(x)=(\frac{\pi}{2}-x)$ , we have the second factor of the right hand side:

$\csc(\frac{\pi}{2}-x)$

Let's just do it all together without all the words now:

$\cot(x)+\cot(\frac{\pi}{2}-x)$

$\cot(x)+\tan(x)$

$\frac{\cos(x)}{\sin(x)}+\frac{\sin(x)}{\cos(x)}$

$\frac{1}{\sin(x)}(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)(\cos(x)+\sin(x)\frac{\sin(x)}{\cos(x)})$

$\csc(x)[\frac{\cos(x)\cos(x)}{\cos(x)}+\sin(x)\frac{sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos(x)\cos(x)+\sin(x)\sin(x)}{\cos(x)}]$

$\csc(x)[\frac{\cos^2(x)+\sin^2(x)}{\cos(x)}]$

$\csc(x)[\frac{1}{\cos(x)}]$

$\csc(x)[\sec(x)]$

$\csc(x)[\csc(\frac{\pi}{2}-x)]$

$\csc(x)\csc(\frac{\pi}{2}-x)$

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3 years ago

Which of the following is a quadratic equation?

Aloiza [94]

Answer:

3) 4x² -1

Step-by-step explanation:

A quadratic equation is a 2nd-degree polynomial equation.

1) an exponential equation (the variable is in the exponent)

2) a cubic equation (degree = 3)

3) a quadratic equation

4) a linear equation (degree = 1)

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1 year ago

Girls to boys 5 to 8. How many girls are in the class if there are 24 boys

ValentinkaMS [17]

Answer:

Step-by-step explanation:

It would be 15 girls to 24 boys

3 0

3 years ago

Read 2 more answers

Drag each label to the correct location on the image.

dolphi86 [110]

Answer:

The answer will be listed below.

Step-by-step explanation:

No Solution: -2z+2+4z=16/5+2z-6/5; 5r+2=6r+3-r

One Solution: 3/2x+2.3-1/2x=4.3+x; 2x+2/3=2x+4/5-4x; 32p-2.5+2.1p=5p-7/2

Infinite Solution: 17/4+4.2y-9/4=2.2y+6+2y-4

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3 years ago

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PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! SUPER IMPORTANT QUESTION!!!

Anettt [7]

Answer:

Distance between two cities is 193.94 miles.

Step-by-step explanation:

We have,

Madison and Wisconsin have latitudes 43.0731°N and 45.9172°N respectively.

Thus, their difference is 45.9172°N - 43.0731°N = 2.8441°

We assumed, the diameter of earth is 7917.5 miles.

So, the radius = $\frac{7917.5}{2}$ = 3958.75 miles

So, using the cosine formula, we have,

$a^{2}=b^{2}+c^{2}-2bc\cos A$

i.e. $a^{2}=3958.75^{2}+3958.75^{2}-2\times 3958.75\times \cos 2.8441$

i.e. $a^{2}=31343403.13\times 0.0012$

i.e. $a^{2}=37612.08$

i.e. a= 193.94 miles.

Hence, the distance between two cities is 193.94 miles.

8 0

2 years ago