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deff fn [24]
3 years ago
5

The publisher of Celebrity Living claims that the mean sales for personality magazines that feature people such as Megan Fox or

Jennifer Lawrence are 1.5 million copies per week. A sample of 10 comparable titles shows a mean weekly sales last week of 1.3 million copies with a standard deviation of 0.9 million copies.

Business
1 answer:
Olin [163]3 years ago
3 0

Answer and Explanation:

The computation is shown below:

For determining each part first we have to do the following calculations

Critical value of t = 3.250

Null hypothesis = 1.5

Alternative hypothesis ≠ 1.5

Population mean \mu = 1.5

Sample mean \bar X= 1.30

Sample size n = 10.00

Sample standard deviation s = 0.900

Standard error of mean is

s_x = \frac{s}{\sqrt{n} }

= \frac{0.900}{\sqrt{10.00}}

= 0.2846

Test static is

t = \frac{x - \mu}{s_x}

= \frac{1.30 - 1.5}{0.2846}

= -0.703

a. The null hypothesis is

μ = 1.5

Alternate Hypothesis is

μ ≠ 1.5

b. reject H_o if t is not between

-3.250 and 3.250

c. The value of the test statistic is

t = -0.703

(as we have computed above)

d. fail to reject H_o as this data does not contradict the publisher claim

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