Answer: The correct option is (A) < .
Step-by-step explanation: We are given to select the correct mathematical symbol that would best fill in the blank to compare the following two real numbers :
First , we need to find the values of both the real numbers in decimal form.
We have
Since, 
so we get
Thus, the correct mathematical symbol is <.
Option (A) is CORRECT.
Answer:
20.25π
Step-by-step explanation:
The circumference (C) of a circle is calculated using the formula
C = 2πr ← r is the radius
given C = 9π, then
2πr = 9π ( divide both sides by 2π )
r = 
( cancel the π on numerator/denominator )
= 4.5
The area (A) of a circle is calculated using the formula
A = πr² = π × 4.5² = 20.25π
The length of each side of the larger square is 8 cm.
<u>Step-by-step explanation</u>:
Step 1 ;
- The combined area of two squares = 80 sq.cm
- The side of small square = x
- The side of larger square = 2x
Step 2 :
Area of the square = a^2
Area of small square + area of large square = 80
x^2 + (2x)^2 = 80
x^2 + 4x^2 = 80
5x^2 = 80
x^2 = 80/5
x^2 = 16
x = ±4
Step 3 :
Since length cannot be negative, the value of x= 4
∴ The length of the side of small square = 4cm
The length of the side of larger square = 2x = 8cm
The graph which represents the solution to the compound inequality is; -2 ≤ x < 5.
<h3>Which graph represents the solution to the compound inequality?</h3>
The inequalities given in the task content can be solved as follows;
For –2x + 4 ≤ 8
-2x ≤ 8 -4
x >= -2
For –2x + 4 > –6
–2x > –6 -4
x < 5
Hence, the graph which represents the solution to the compound inequality is; -2 ≤ x < 5.
Read more on compound inequality;
brainly.com/question/7070563
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Answer:
-30√(t/a) cos(√(at)) + 30/a sin(√(at)) + C
Step-by-step explanation:
∫ 15 sin(√(at)) dt
Use substitution:
If x = √(at), then:
dx = ½ (at)^-½ (a dt)
dx = a / (2√(at)) dt
dx = a/(2x) dt
dt = (2/a) x dx
Plugging in:
∫ 15 sin x (2/a) x dx
30/a ∫ x sin x dx
Integrate by parts:
If u = x, then du = dx.
If dv = sin x dx, then v = -cos x.
∫ u dv = uv − ∫ v du
= 30/a (-x cos x − ∫ -cos x dx)
= 30/a (-x cos x + ∫ cos x dx)
= 30/a (-x cos x + sin x + C)
Substitute back:
30/a (-√(at) cos(√(at)) + sin(√(at)) + C)
-30√(t/a) cos(√(at)) + 30/a sin(√(at)) + C
