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3 years ago

Jaime runs 2/3 of a mile in 1/6 of an hour. What is her unit rate, in miles per hour?

Mathematics

2 answers:

dsp733 years ago

5 0

Best answer is 4 miles

kifflom [539]3 years ago

4 0

1/6 of an hour is 10 minutes, so Jaime runs 2/3 of a mile in 10 minutes. To find how far she runs in 10 minutes, we will multiply 2/3 times 6 to get to the full 60 minutes.

2/3 • 6 = 4, so Jaime runs 4 miles per hour. (C)

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Jacob’s daily tips this work week were $99, $78, $58, $91, $90, and $68. Is Jacob correct in thinking that the mean best represe

alexandr1967 [171]

Jacob is correct in thinking that because the mean represents the average of several quantities

3 0

3 years ago

Read 2 more answers

Debra plans to invest $2,250 for 10 years. She can invest in a savings account that pays 4% simple intrest or a savings account

Diano4ka-milaya [45]

Answer:

$\$180.55$

Step-by-step explanation:

step 1

Simple interest

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04$

substitute in the formula above

$A=2,250(1+0.04*10)$

$A=2,250(1.4)$

$A=\$3,150$

step 2

Interest compounded annually

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04\\n=1$

substitute in the formula above

$A=2,250(1+\frac{0.04}{1})^{1*10}$

$A=2,250(1.04)^{10}$

$A=\$3,330.55$

step 3

Find the differences between the two final amounts

$A=\$3,330.55-\$3,150=\$180.55$

5 0

3 years ago

How many equivalence relations are there on the set 1, 2, 3]?

Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

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3 years ago

Plssssss help meh with this

Naddik [55]

Answer:

<h2>ᎪꪀsωꫀᏒ</h2>

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Step-by-step explanation:

-3x²-20

-3(-9)²-20

-3(81)-20

-243-20

-263

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2 years ago

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What is 9.2 as a fraction

Maru [420]

It is 3 1/8 because 9.2 is a decimal and a fraction is 3 1/8 and a mixed fraction is 3 7/8

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3 years ago