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NARA [144]
3 years ago
12

Simplify. (-3x?yz?)(-2x2y323)

Mathematics
1 answer:
Elis [28]3 years ago
8 0
The answer is -12x^(6)y^(7)z^(9)
Add the exponents together
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What is 4x(1+8x) Distributed
MA_775_DIABLO [31]

Answer:

4x + 32x²

Step-by-step explanation:

4x(1 + 8x) ← multiply each term in the parenthesis by 4x

= 4x + 32x²

4 0
3 years ago
Solve the problem. WILL GIVE BRAINLIEST
vaieri [72.5K]
<span>5  x  4    
--     --    = </span> 5 × 48 × 15 = 20/120<span><span><span>
8</span> × 15      </span><span>After reducing the fraction, the answer is <span>1/6</span></span></span>
8 0
3 years ago
Solve the following equations 3m = 2(m - 3)​ its on acellus! pls help!!
Sergio039 [100]

Answer:

m = -6

Step-by-step explanation:

3m = 2(m - 3)​

Distribute

3m = 2m - 6

Subtract 2m from each side

3m -2m = 2m-2m -6

m = -6

7 0
3 years ago
Read 2 more answers
A circle is drawn within a square as shown.
Yakvenalex [24]

As it is shown in the figure, the length of the square's side  s  is also the length of the circle's diameter  d:

s = d = 28 in.


•  Computing the area of the square:

A₁ = s²

A₁ = 28²

A₁ = 28 × 28

A₁ = 784 in²          ✔


•  Computing the area of the circle:

A₂ = π × r²

A₂ = π × (d/2)²

A₂ = π × (28/2)²

A₂ = π × 14²

A₂ ≈ 3.14 × 14 × 14

A₂ ≈ 615.44 in²          ✔

—————

•  The area of the shaded portion is equal to the difference between the area of the square and the area of circle:

A = A₁ – A₂

A ≈ 784 – 615.44

A ≈ 168.56 in²    <———   this is the answer (1st option).


I hope this helps. =)

8 0
3 years ago
I need help in partial fraction!! With simple explaination would be nice!
WITCHER [35]
\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}

The degree of the numerator (4) is larger than the degree of the denominator (3), so first you need to divide. (Added screenshot of long division procedure.)

\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x-\dfrac{4x^2-17x+10}{x(x^2-3)}

Now the second term can be decomposed into partial fractions.

\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1}x+\dfrac{r_2x+r_3}{x^2-3}
\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1(x^2-3)+x(r_2x+r_3)}{x(x^2-3)}
4x^2-17x+10=r_1(x^2-3)+x(r_2x+r_3)
4x^2-17x+10=(r_1+r_2)x^2+r_3x-3r_1
\implies\begin{cases}r_1+r_2=4\\r_3=-17\\-3r_1=10\end{cases}\implies r_1=-\dfrac{10}3,r_2=\dfrac{22}3,r_3=-17=-\dfrac{51}3
\implies\dfrac{4x^2-17x+10}{x(x^2-3)}=-\dfrac{10}{3x}+\dfrac{22x-51}{x^2-3}

So

\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x+\dfrac{10}{3x}-\dfrac{22x-51}{x^2-3}

3 0
3 years ago
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