Soo what do you need help with? It seems pretty easy. I can help you if you want.
9514 1404 393
Answer:
- Translate P to E; rotate ∆PQR about E until Q is coincident with F; reflect ∆PQR across EF
- Reflect ∆PQR across line PR; translate R to G; rotate ∆PQR about G until P is coincident with E
Step-by-step explanation:
The orientations of the triangles are opposite, so a reflection is involved. The various segments are not at right angles to each other, so a rotation other than some multiple of 90° is involved. A translation is needed in order to align the vertices on top of one another.
The rotation is more easily defined if one of the ∆PQR vertices is already on top of its corresponding ∆EFG vertex, so that translation should precede the rotation. The reflection can come anywhere in the sequence.
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<em>Additional comment</em>
The mapping can be done in two transformations: translate a ∆PQR vertex to its corresponding ∆EFG point; reflect across the line that bisects the angle made at that vertex by corresponding sides.
<span>cube has six identical walls
96ft</span>²<span> : 6 = 6 ft</span>²<span> - </span>one wall surface
<span>pattern on the surface of the cube
</span>A = a²
a - <span>the edge of the cube
A = a</span>² ⇔ a=√A
a = √(16ft)² = 4ft
V = volume
V = a³
V = (4ft)³ = 64 ft³
Answer:
I think it is 4 to 3
Step-by-step explanation:
if I am wrong I'm sorry
Answer:
j
Step-by-step explanation:
