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Sphinxa [80]
3 years ago
12

F(x)=|3x+5|+6 g(x)=7 find (f+g) (x).

Mathematics
1 answer:
horrorfan [7]3 years ago
8 0

Answer:

(f+g) (x)=\mid 3x+5\mid+13

Step-by-step explanation:

<u>Operation of Functions</u>

Given:

f(x)=\mid 3x+5\mid+6

g(x)=7

The sum of (f+g) (x) is:

(f+g) (x)=\mid 3x+5\mid+6+7

We cannot operate with the expression inside the absolute bars, thus:

\boxed{(f+g) (x)=\mid 3x+5\mid+13}

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Steve gets paid $50 a week plus $5 for each item he sells. He wants to know how many items he
Charra [1.4K]

<u>Answer:</u>

$50 + 5x > $220

5x> $220 - $50

7 0
3 years ago
What equation in slope intercept form represents the line that passes through the two point? (6.9,5.9), (10.9,-2.1)
den301095 [7]

Answer:

y = 2x + b

I dont know what b is but the slope is 2 I think

6 0
3 years ago
Help I really don’t understand this
MAXImum [283]
Let x=3.77777777...
10x=37.777777777...
9x=10x-x=34
9x=34 so x=34/9=3 7/9
3 0
3 years ago
Tickets for a dance recital cost $15 for adults and $7 for children. The dance company sold 253 tickets, and the total receipts
elixir [45]

Answer:

Adult tickets =125

Child tickets = 128

Step-by-step explanation:

Let the number of adult and children tickets sold be x and y respectively

So that

x+y= 253--------1

Since total sales/receipt is $2,771

And given that tickets for a dance recital cost $15 for adults and $7 for children hence

15x+7y= 2771-------2

Solving equation 1 and 2 simultaneously we have

x+y= 253---------------1

15x+7y= 2771----------2

Let us multiply equation 1 by 15 to get equation 3 to eliminate x and subtract equation 2 from 3

15x+15y=3795---------3

-{15x+7y= 2771----------2

0+8y=1024

8y= 1024

y= 1024/8

y= 128 tickets

So solve for x let us put y= 128 in equation 1

x+ 128=253

x=253-128

x= 125 tickets

8 0
3 years ago
Which expression is equivalent
Tatiana [17]

Given expression is

\sqrt[4]{\frac{16x^{11}y^8}{81x^7y^6}}

Radical is fourth root

first we simplify the terms inside the radical

\frac{x^{11}}{x^7}=x^4

\frac{y^(8)}{y^6}=y^2

So the expression becomes

\sqrt[4]{\frac{16x^4y^2}{81}}

Now we take fourth root

\sqrt[4]{16} = 2

\sqrt[4]{81} = 3

\sqrt[4]{x^4} = x

We cannot simplify fourth root (y^2)

After simplification , expression becomes

\frac{2x\sqrt[4]{y^2}}{3}

Answer is option B


8 0
3 years ago
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