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Sphinxa [80]
3 years ago
12

F(x)=|3x+5|+6 g(x)=7 find (f+g) (x).

Mathematics
1 answer:
horrorfan [7]3 years ago
8 0

Answer:

(f+g) (x)=\mid 3x+5\mid+13

Step-by-step explanation:

<u>Operation of Functions</u>

Given:

f(x)=\mid 3x+5\mid+6

g(x)=7

The sum of (f+g) (x) is:

(f+g) (x)=\mid 3x+5\mid+6+7

We cannot operate with the expression inside the absolute bars, thus:

\boxed{(f+g) (x)=\mid 3x+5\mid+13}

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Over the last 3  evenings, Keisha received a total of 81  phone calls at the call center. The first evening, she received 6  few
tensa zangetsu [6.8K]

Answer:

First: 15

Second: 21

Third: 45

Step-by-step explanation:

In order to create the equation we need to represent the evenings with an alebraic term, in thsi case we are going to represent the second evening with an X

Second evening:x

The first night she got 6 fewer calls than the second: Second-6=x-6

The third night she received 3 times the first: 3(first night)=3(x-6)

The equation is First Night plus second night plus third night equals 81.

First+second+third=81\\x+(x-7)+3(x-6)=81\\x+x-7+3x-18=81\\5x=81+21+6\\5x=105\\x=\frac{105}{5} \\x=21

So the first evening he received 15 calls, the second he received 21 and the third one he received 45.

8 0
3 years ago
72 students in sixth grade at Cypress Middle school like pumkin Spice Oreos.If there are 300 Sixth grade students,what percent o
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Answer:

19.35

Step-by-step explanation:

6 0
2 years ago
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A correct translation of "six less than twice the value of x" is
Wittaler [7]

"six less" = -6

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2x-6


5 0
3 years ago
Find the value of y.<br><br> m ∠ 1 = 3y - 6
Ivenika [448]
m\angle1=90\\&#10;3y-6=90\\&#10;3y=96\\&#10;y=32
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Given: \overline{AC} \perp \overline{BD} AC ⊥ BD and \overline{BD} BD bisects \overline{AC}. AC . Prove: \triangle ABD \cong \tr
Fofino [41]

Answer:

The Proof for

△ABD ≅ △CBD is below

Step-by-step explanation:

Given:

\overline{AC} \perp \overline{BD}

\overline{BD} \ bisects\  \overline{AC}

AD = CD      .........BD bisect AC

To Prove:

△ABD ≅ △CBD

Proof:

In  ΔABD  and ΔCBD  

BD ≅ BD              ....……….{Reflexive Property}

∠ADB ≅ ∠CDB    …………..{Measure of each angle is 90°( \overline{AC} \perp \overline{BD} )}

AD ≅ CD              ....……….{ \overline{BD} \ bisects\  \overline{AC} }

ΔABD  ≅ ΔCBD   .......….{By Side-Angle-Side Congruence test}  ...Proved

4 0
3 years ago
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