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vagabundo [1.1K]
3 years ago
13

If g(x) =15-3(x-9),what is g(-4)

Mathematics
1 answer:
UNO [17]3 years ago
5 0

Answer: " 6."

Step-by-step explanation: "If a horizontal line intersects the graph of f(x) in more than one point, .... If f has an inverse function, f-1, and you happen to know that f-1(15) = 3, ... 3.) If g(-10) = 5, what is g-1(5)?. 4.) If g-1(6) = 8, what is g(8)?. 5.) If g-1(0) = 9, what is g(9)?.

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Solve (x) F(x)=x^2+3x-2
zaharov [31]
Solve (x) F(x)=x^2+3x-2  is x-2
6 0
3 years ago
A pair of sneakers originally cost $90. If sales tax is 8%, what is the final price of the sneakers?
tatyana61 [14]

Answer:

Step-by-step explanation:

Ello again!

Ok so you would turn the percent into a decimal again 8% ↠ 0.8

then you would multiply the decimal and money 90 × 0.8 =  72

Hope dis helped FAM

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5 0
3 years ago
4x-6 > 10 and 4x-6<30?
AlladinOne [14]

Answer:

wrong 4 x 6 = 24 so 24 > 10        and 4 x 6 = 24 so 24  <  30

Step-by-step explanation:

hope it help ;)

8 0
3 years ago
A suspension bridge with weight uniformly distributed along its length has twin towers that extend 70 meters above the road surf
goblinko [34]

Answer:

  17.5 m

Step-by-step explanation:

The height of a parabola above its vertex is proportional to the square of the distance from the vertex.

<h3>Cable height</h3>

The towers are 1200 m apart, so each is 600 m from center. The location of interest is 300 m from center, so 1/2 the distance to a tower. Since the height is proportional to the square of the distance, the height half-way to the tower will be (1/2)² = 1/4 the height of the tower.

  (1/2)²×(70 m) = 17.5 m

The height of the cable 300 m from center will be 17.5 meters.

7 0
2 years ago
Be sure to answer all parts. List the evaluation points corresponding to the midpoint of each subinterval to three decimal place
gayaneshka [121]

Answer:

The Riemann Sum for \int\limits^5_4 {x^2+4} \, dx with n = 4 using midpoints is about 24.328125.

Step-by-step explanation:

We want to find the Riemann Sum for \int\limits^5_4 {x^2+4} \, dx with n = 4 using midpoints.

The Midpoint Sum uses the midpoints of a sub-interval:

\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f\left(\frac{x_0+x_1}{2}\right)+f\left(\frac{x_1+x_2}{2}\right)+f\left(\frac{x_2+x_3}{2}\right)+...+f\left(\frac{x_{n-2}+x_{n-1}}{2}\right)+f\left(\frac{x_{n-1}+x_{n}}{2}\right)\right)

where \Delta{x}=\frac{b-a}{n}

We know that a = 4, b = 5, n = 4.

Therefore, \Delta{x}=\frac{5-4}{4}=\frac{1}{4}

Divide the interval [4, 5] into n = 4 sub-intervals of length \Delta{x}=\frac{1}{4}

\left[4, \frac{17}{4}\right], \left[\frac{17}{4}, \frac{9}{2}\right], \left[\frac{9}{2}, \frac{19}{4}\right], \left[\frac{19}{4}, 5\right]

Now, we just evaluate the function at the midpoints:

f\left(\frac{x_{0}+x_{1}}{2}\right)=f\left(\frac{\left(4\right)+\left(\frac{17}{4}\right)}{2}\right)=f\left(\frac{33}{8}\right)=\frac{1345}{64}=21.015625

f\left(\frac{x_{1}+x_{2}}{2}\right)=f\left(\frac{\left(\frac{17}{4}\right)+\left(\frac{9}{2}\right)}{2}\right)=f\left(\frac{35}{8}\right)=\frac{1481}{64}=23.140625

f\left(\frac{x_{2}+x_{3}}{2}\right)=f\left(\frac{\left(\frac{9}{2}\right)+\left(\frac{19}{4}\right)}{2}\right)=f\left(\frac{37}{8}\right)=\frac{1625}{64}=25.390625

f\left(\frac{x_{3}+x_{4}}{2}\right)=f\left(\frac{\left(\frac{19}{4}\right)+\left(5\right)}{2}\right)=f\left(\frac{39}{8}\right)=\frac{1777}{64}=27.765625

Finally, use the Midpoint Sum formula

\frac{1}{4}(21.015625+23.140625+25.390625+27.765625)=24.328125

This is the sketch of the function and the approximating rectangles.

5 0
4 years ago
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