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1 year ago

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The sum of thrice a number and 5 is greater than or equal to the sum of twice a number and 1. Write down the inequality and solv

e it..

1 answer:

sertanlavr [38]1 year ago

7 0

Answer:

May be helpful.

thx.......

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Use the graph of the function. Determine Over what interval(s) the function is positive or negative.

san4es73 [151]

Answer:

I can't see the numbers well, but the graph is decreasing from (-inf, minimum) and increasing from (minimum, inf). The minimum is the vertex. Hope this helps!

Step-by-step explanation:

4 0

2 years ago

Which of the following correctly rearranged the equation to represent solution for x in terms of y and a

Maksim231197 [3]

$x=\frac{y-5}{a}$

6 0

2 years ago

Integrate the following. ∫<img src="https://tex.z-dn.net/?f=5x%5E%7B4%7D%20dx" id="TexFormula1" title="5x^{4} dx" alt="5x^{4} dx

Vadim26 [7]

Answer:

$\displaystyle D) {x}^{5} + \rm C$

Step-by-step explanation:

we would like to integrate the following Integral:

$\displaystyle \int 5 {x}^{4} \, dx$

well, to get the constant we can consider the following Integration rule:

$\displaystyle \int c{x} ^{n} \, dx = c\int {x}^{n} \, dx$

therefore,

$\displaystyle 5\int {x}^{4} \, dx$

recall exponent integration rule:

$\displaystyle \int {x} ^{n} \, dx = \frac{ {x}^{n + 1} }{n + 1}$

so let,

$n = 4$

Thus integrate:

$\displaystyle = 5\left( \frac{ {x}^{4+ 1} }{4 + 1} \right)$

simplify addition:

$\displaystyle = 5\left( \frac{ {x}^{5} }{5} \right)$

reduce fraction:

$\displaystyle = {x}^{5}$

finally we of course have to add the constant of integration:

$\displaystyle \boxed{ {x}^{5} + \rm C}$

hence,

our answer is D)

7 0

2 years ago

Read 2 more answers

Please answer this question now

alisha [4.7K]

Answer:

If it's not too late by now, the answer is 19.9 $mm^{2}$

3 0

2 years ago

1 1/5 to the power of 3-1

Angelina_Jolie [31]

This is 6/5 to the 2 (6/5 squared). 36/25 is the answer

4 0

3 years ago