HELP!!! WILL AWARD BRAINLIEST!!!
2 answers:
First, solve 10x + y = -20 for y: y = -20 - 10x
Next, substitute -20 -10x for y in the second equation:
-20 - 10x = 2x^2 - 4x - 16.
Rearranging, 2x^2 + 6x + 4 = 0
Simplifying, x^2 + 3x + 2 = 0
The roots of this poly eqn are -1 and -2. Therefore, x = -1 and x = -2.
One by one, subst. these x-values into y = -20 - 10x to find the corresponding y-values.
Your answers should look like this: (-1, y) and (-2, y) (different values for y).
From the first equation
y = -20 - 10x
Substitute for y in second equation:-
2x^2 - 4x - 16 = -20 - 10x
2x^2 + 6x + 4 = 0
2(x^2 + 3x + 2) = 0
2(x + 1)(x + 2) = 0
so x = -1, -2
When x = -1, y = -20 +10 = -10
when x = -2, y = -20 + 20 = 0
answer is (-1, -10) and ( -2 , 0)
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