Question

HELP!!! WILL AWARD BRAINLIEST!!!

Answer 1

First, solve 10x + y = -20 for y:    y = -20 - 10x

Next, substitute -20 -10x for y in the second equation:

-20 - 10x = 2x^2 - 4x - 16.

Rearranging, 2x^2 + 6x + 4 = 0

Simplifying, x^2 + 3x + 2 = 0

The roots of this poly eqn are -1 and -2.  Therefore, x = -1 and x = -2.

One by one, subst. these x-values into   y = -20 - 10x   to find the corresponding y-values.  

Your answers should look like this:  (-1, y) and (-2, y)   (different values for y).

Answer 2

From the first equation
y = -20 - 10x

Substitute for y in second equation:-
2x^2 - 4x - 16 = -20 - 10x
2x^2 + 6x + 4 = 0
2(x^2 + 3x  + 2)  = 0
2(x + 1)(x + 2) = 0

so x = -1, -2
When x = -1, y =  -20 +10 = -10
when x = -2,  y = -20 + 20 = 0

answer is (-1, -10) and ( -2 , 0)