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3 years ago

PLEASE HELP! I need someone to help me with my home work is anyone able to help?

Mathematics

1 answer:

Monica [59]3 years ago

8 0

Answer:

Katie

Step-by-step explanation:

Use seconds as the standard unit to compare the speeds of the 4 runners

Tony is already in standard form and runs 12 ft/s

Katie:

450/30

15 ft/s

Frank:

1 mile = 5280 feet

5280/577

9.15 ft/s

Adam:

I minute = 60 seconds

880/60

14.67 ft/s

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Suppose that the epidemiologist wants to re-estimate the population proportion and wishes for her 95% confidence interval to hav

Svetllana [295]

Answer:

She needs a sample of at least 385.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

How large a sample should she take to achieve this?

She needs a sample of size at least n.

n is found when M = 0.04.

We do not know the true population proportion, so we use $\pi = 0.5$ , which is the case for which we are going to need the largest sample size.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.05 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.05\sqrt{n} = 1.96*0.5$

Dividing both sides by 0.05

$\sqrt{n} = 19.6$

$(\sqrt{n})^{2} = 19.6^{2}$

$n = 384.2$

Rounding up

She needs a sample of at least 385.

3 0

3 years ago

A teacher has 96 pencils to give to her students. If they came in boxes of 6, how many boxes of pencils does she have?

exis [7]

Answer: She had 16 boxes of pencils.

Step-by-step explanation: Divide 96 by 6 to get 16.

6 0

2 years ago

Read 2 more answers

Please solve for the inverse variation equation

mojhsa [17]

Answer:

f(x) = $\frac{1}{x-2} + 1$

Step-by-step explanation:

First we identify the Vertical Asymptote. Which is at x = 2

The function has a VA only at the point where the denominator gives 0, so because we know x = 2 is the VA, the denominator will be x - 2.

Then we identify the Horizontal Asymptote, which is the behavior of the function for very large 'x', or the horizontal line of the graph on the y - axis. Which is at y = 1. So our function will go to 1, as x grows incredibly large.

But since our denominator is x - 2, the top remains 1, but we should add a 1 to the function so it really has a HA at y = 1.

f(x) = $\frac{1}{x-2} + 1$

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3 years ago

Geometry First Semester.<br>Can someone please help with this?

Len [333]

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3 years ago

A candy machine is filled with candy. The weight of the candy can differ from the desired 84 ounce weight by no more than 0.5 ou

ANEK [815]

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