<h3><u>L</u><u>H</u><u>S</u><u>:</u><u>-</u></h3>
![\\ \sf\longmapsto 1+tan^2A](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%201%2Btan%5E2A)
![\boxed{\sf tanA=\dfrac{sinA}{cosA}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20tanA%3D%5Cdfrac%7BsinA%7D%7BcosA%7D%7D)
![\\ \sf\longmapsto 1+\dfrac{sin^2A}{cos^2A}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%201%2B%5Cdfrac%7Bsin%5E2A%7D%7Bcos%5E2A%7D)
![\\ \sf\longmapsto \dfrac{cos^2A+sin^2A}{cos^2A}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7Bcos%5E2A%2Bsin%5E2A%7D%7Bcos%5E2A%7D)
![\boxed{\sf cos^2A+sin^2A=1}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20cos%5E2A%2Bsin%5E2A%3D1%7D)
![\\ \sf\longmapsto \dfrac{1}{cos^2A}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B1%7D%7Bcos%5E2A%7D)
![\\ \sf\longmapsto \dfrac{1}{1-sin^2A}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B1%7D%7B1-sin%5E2A%7D)
![\\ \sf\longmapsto \dfrac{1}{1}-\dfrac{1}{sin^2A}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B1%7D%7B1%7D-%5Cdfrac%7B1%7D%7Bsin%5E2A%7D)
![\\ \sf\longmapsto \dfrac{1}{sin^2A}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B1%7D%7Bsin%5E2A%7D)
Hence verified
Answer:
Step-by-step explanation:
m ∠XOY = m ∠WOV
so, m XY = m WV --- (i)
{ If angle subtended by two arcs at the center are equal, then length of arc are equal}
m YZ = m ZW ------- (ii) {given}
Add (i) and (ii)
XY + YZ = WV + ZW
XZ = ZV
Hence proved.
Answer:
b=6
a=6
hypotenuse=6√ 2
Step-by-step explanation:
This is a 45, 45, 90 triangle. This means a=b and hypotenuse is equal to b times √ 2. This means that you have to divide the hypotenuse by √ 2 to get what b is equal to 6√ 2 divided by √ 2 is equal to 6. Therefore, b=6. Because b and a are equal, a is also equal to 6. Therefore, b=6, a=6.
If this helps please mark as brainliest
Answer:
b
Step-by-step explanation: