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m_a_m_a [10]
3 years ago
12

Walnut High Schools Enrollment is exactly five times as large as the enrollment at walmut junior high the total enrollment for t

he two schools is 852 what is the enrollment at each school​
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0

Answer:

Enrollment at walnut junior = 142

Enrollment at walnut high = 710

Step-by-step explanation:

Let :

Enrollment at walnut junior = x

Enrollment at walnut high = 5x

Total enrollment in both schools = 852

Mathematically ;

x + 5x = 852

6x = 852

x = 142

5x = 142 * 5 = 710

Hence,

Enrollment at walnut junior = 142

Enrollment at walnut high = 710

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In this figure what is m 5?​
Harlamova29_29 [7]

Answer:

m<5 = 95 degrees

Step-by-step explanation:

Let's first find m<1

=> m<1 = 180-85

=> m<1 = 95 degrees

Since,

m<1 = m<5 (Corresponding angles)

So,

m<5 = 95 degrees

3 0
3 years ago
PLS HELP!!!! LOOK AT PICTURE!
kakasveta [241]

Answer:

Side*side= 0.5625 inch

Step-by-step explanation:

8 0
3 years ago
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Which ones do I choose
weeeeeb [17]
It should be B because is a minus is in front of something that is a negative they change to be positive

7 0
3 years ago
Assume that for a particular tire brand, the probability of wearing out before 30,000 miles is 0.25. For someone who buys a set
Hatshy [7]

Answer:

The probability that all will last at least 30,000 miles is 0.3164.

Step-by-step explanation:

Consider the provided information.

For a particular tire brand, the probability of wearing out before 30,000 miles is 0.25. Someone who buys a set of four of these tires,

That means the probability of not wearing out is 1-0.25 = 0.75

Now use the binomial distribution formula.

^nC_r (p^{n-r})(q^r)

Substitute p = 0.25, q=0.75, r=4 and n=4

^4C_4 (0.25)^{4-4}(0.75)^4

1 \times 0.75^4

0.3164

The probability that all will last at least 30,000 miles is 0.3164.

8 0
4 years ago
PLEASE HELP
s344n2d4d5 [400]
Let the length of the diameter be d and radius be r, thus to solve for d we proceed as follows:
r²+31²=(r+15)²
solving for d we solve for r
r²+961=r²+30r+225
putting like terms together we obtain:
r²-r²+961-225=30r
736=30r
solving for r
r=24.53
thus
d=24.5333×2
d=49.067~49.1
Answer is D. 49.1

7 0
3 years ago
Read 2 more answers
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