To determine the probability that exactly two of the five marbles are blue, we will use the rule of multiplication.
Let event A = the event that the first marble drawn is blue; and let B = the event that the second marble drawn is blue.
To start, it is given that there are 50 marbles, 20 of them are blue. Therefore, P(A) = 20/50
After the first selection, there are 49 marbles left, 19 of them are blue. Therefore, P(A|B) = 19/49
Based on the rule of multiplication:P(A ∩ B) = P(A)*P(A|B)P(A ∩ B) = (20/50) (19/49)P(A ∩ B) = 380/2450P(A ∩ B) = 38/245 or 15.51%
The probability that there will be two blue marbles among the five drawn marbles is 38/245 or 15.51%
We got the 15.51% by dividing 38 by 245. The quotient will be 0.1551. We then multiplied it by 100% resulting to 15.51%
<span>2y = 4x + 8 ------> y = 2x + 4
4y = 4x + 20 ------> y = x+5
2x+4 =x+5
x = 1
y=x+5=1+5=6
Check:
</span>2*6 = 4*1 + 8 , 12 =12
4*6 = 4*1 + 20, 24 =24<span>
x=1,y=6
(1,6)
</span>
Answer:
The inverse f-1(x) = ( x - 2) / 2.
Step-by-step explanation:
Let 2x + 1 = y
Now find x in terms of y:
2x = y - 1
x = (y - 1) / 2
Replace the x by the inverse f-1(x) and the y by x, so we have:
f-1(x) = ( x - 2) / 2.
