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3 years ago

5y-5y^2-5+2+2y+3y^2-1

Mathematics

2 answers:

Sliva [168]3 years ago

7 0

Answer: -2y^2+7y-4

Step-by-step explanation:

Combine -5y^2 and 3y^2 to get -2y^2.

Combine 5y and 2y to get 7y.

Combine -5, 2, and -1 to get -4.

Put these in order with the highest exponent first.

-2y^2+7y-4

LiRa [457]3 years ago

6 0

5y-5y^2-5+2+2y+3y^2-1

collect like terms

7y-2y^2-4

reorder the terms

-2y^2+7y-4

-2y^2+7y-4 is your final answer, I hope this helps!

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3 years ago

BRAINLIEST ANSWER AND 98 POINTS!!!!

Alex73 [517]

Answer:

P (g1, g2) = P(g1) * P(g2) = 1/2 * 1/2 = 1/4

P (r1, r2) = P(r1) * P(r2) = 1/5 * 1/5 = 1/25

P ( b1, g1 or g1 b2) = 3/20 + 3/20 = 6/20 = 3/10

P ( b1, g1 or g1 b2) = 1/10 + 1/10 = 2/10 = 1/5

Step-by-step explanation:

How many marbles are there?

5 green, 3 black, and 2 red marbles = 10 marbles

P ( green marbles) = green/ total = 5/10 = 1/2

Then she puts it back, so there are still 10 marbles

P (2nd marble is green) = green/ total = 5/10 = 1/2

These are independent events ( since the marble is replaced)

P (g1, g2) = P(g1) * P(g2) = 1/2 * 1/2 = 1/4

P ( red marble) = red/ total = 2/10 = 1/5

Then she puts it back, so there are still 10 marbles

P (2nd marble is red) = red/ total = 2/10 = 1/5

These are independent events ( since the marble is replaced)

P (r1, r2) = P(r1) * P(r2) = 1/5 * 1/5 = 1/25

P ( black marble) = black/ total = 3/10

Then she puts it back, so there are still 10 marbles

P (2nd marble is green) = green/ total = 5/10 = 1/2

These are independent events ( since the marble is replaced)

P (b1, g2) = P(b1) * P(g2) = 3/10 * 1/2 = 3/20

This is if order matters, but I will assume order does not matter since the key word then is not there it just says and

If order doesn't matter, just that she has a black and green marble

The we multiply it by 2 because

P (b2, g1) = P(b2) * P(g1) = 1/2 * 3/10 = 3/20

We add the probabilities when it is or

P ( b1, g1 or g1 b2) = 3/20 + 3/20 = 6/20 = 3/10

P ( green marble) = green/ total = 5/10=1/2

Then she puts it back, so there are still 10 marbles

P (2nd marble is red) = red/ total = 2/10 = 1/5

These are independent events ( since the marble is replaced)

P (g1, r2) = P(g1) * P(r2) = 1/2 * 1/5 = 1/10

This is if order matters but I will assume order does not matter since the key word then is not there it just says and

If order doesn't matter, just that she has a green and red marble

The we multiply it by 2 because

P (r1, g2) = P(r1) * P(g2) = 1/5 * 1/2 = 1/10

We add the probabilities when it is or

P ( b1, g1 or g1 b2) = 1/10 + 1/10 = 2/10 = 1/5

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3 years ago