We know for our problem that Rachel makes $10 per hour. Since
represent the number of hours that she works,
will be the total amount that she will make for working
hours. We also know that she sells bracelets for $5 each. Since
represents the number of of bracelets that she sells,
will be her total revenue for selling
bracelets. We also know that she needs to earn at least $200 a week to cover her expenses, so the sum of
and
must be equal or greater than 200:
We can conclude that <span>the graphs that shows the inequality that represents this situation, with its solution region shaded is:</span>
Answer:
540
Step-by-step explanation:
1. We assume, that the number 900 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 900 is 100%, so we can write it down as 900=100%.
4. We know, that x is 3.5% of the output value, so we can write it down as x=3.5%.
5. Now we have two simple equations:
1) 900=100%
2) x=3.5%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
900/x=100%/3.5%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 3.5% of 900
900/x=100/3.5
(900/x)*x=(100/3.5)*x - we multiply both sides of the equation by x
900=28.571428571429*x - we divide both sides of the equation by (28.571428571429) to get x
900/28.571428571429=x
31.5=x
x=31.5
now we have:
3.5% of 900=31.5
Answer:
a)0.08 , b)0.4 , C) i)0.84 , ii)0.56
Step-by-step explanation:
Given data
P(A) = professor arrives on time
P(A) = 0.8
P(B) = Student aarive on time
P(B) = 0.6
According to the question A & B are Independent
P(A∩B) = P(A) . P(B)
Therefore
& 
is also independent
= 1-0.8 = 0.2
= 1-0.6 = 0.4
part a)
Probability of both student and the professor are late
P(A'∩B') = P(A') . P(B') (only for independent cases)
= 0.2 x 0.4
= 0.08
Part b)
The probability that the student is late given that the professor is on time
= 
= 
= 0.4
Part c)
Assume the events are not independent
Given Data
P
= 0.4
=
= 0.4
= 0.4 x P
= 0.4 x 0.4 = 0.16
= 0.16
i)
The probability that at least one of them is on time
= 1-
= 1 - 0.16 = 0.84
ii)The probability that they are both on time
P
= 1 - 
= 1 - ![[P({A}')+P({B}') - P({A}'\cap {B}')]](https://tex.z-dn.net/?f=%5BP%28%7BA%7D%27%29%2BP%28%7BB%7D%27%29%20-%20P%28%7BA%7D%27%5Ccap%20%7BB%7D%27%29%5D)
= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56
Divide number of guitars by 100% and multiply into discount given
149/100 x 29
1.49 x 29
43.21
$43.21 had been removed
Therefore $105.79 is the guitar cost after discount
Hope it was useful ☻
Absolute value= opposite. (positive turns into negative)(negative turns into positive)
