Complete the solution of the equation. Find the value of y when x equals 9. 3x + 4y = 43

1 answer:

5 0

3(9) +4y=43
27 + 4y =43
-27. -27
4y=16
Divide 4 on each side
ANSWER: y=4

You have to go down in the order and end up trying to get y by itself.

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Johnny invested $1000 in savings account that yields 2% interest annually. How much will Johnny's investment be worth in 10 year

Ann [662]

Calculate the interest in a year
Multiply the annual percentage of interest by the investment to find the interest.
interest in a year = 2% × 1,000
interest in a year = 0.02 × 1,000
interest in a year = 20
The annual interest is $20

Calculate the interest after 10 years
Multiply the annual interest by 10
interest 10 years = 20 × 10
interest 10 years = 200
The sum of interest after 10 years is $200

Find total investment
investment = first investment + interest in 10 years
investment = 1,000 + 200
investment = 1,200

The investment will be worth $1,200 in 10 years

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iren2701 [21]

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2 years ago

jamal is making pancakes. He has 6 3/4 cups of batter, but he needs a total of 12 cups. How much more batter does Jamal need?

vampirchik [111]

Jamil has already 6 3/4 cups of butter.
He need 12. SO in order to get the needed butter, we subtract 6 3/4 to 12.

= 12 - 6 3/4
= 11 4/4 - 6 3/4
= 5 1/4

So Jamil needs 5 1/4 cups of butter to achieve the 12 cups.

8 0

2 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$