Find the probability that there are no H when a fair coin is flipped three times.
1 answer:
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Answer:
Using the information from the question, one can construct two equations:
... (1)
... (2)
by substituting (1) into (2) to find x
\frac{5}{4z} = \frac{1}{4}
⇒ z = 5
By substituting value of z into (1)
⇒ 4 (5) = x
⇒ x = 20
Thus the two numbers are 5 & 20
by substituting (1) into (2) to find x
\frac{5}{4z} = \frac{1}{4}
⇒ z = 5
By substituting value of z into (1)
⇒ 4 (5) = x
⇒ x = 20
Thus the two numbers are 5 & 20