D = rt. The first car's rate is r, and the other one, going faster, is r + 12. The time they travel is 2 hours. Since one is going faster than the other, he has gotten farther. But, regardless of that, the distance between them is 232. So the distance the first one travels, r*t, which 2r, plus the distance the second one travels, 2(r+12) = 232. 2r + 2r + 24 = 232. Solve for r. 4r = 208 and r = 52. The slower one goes 52 and the faster one goes 64
3/4 + 5/16
=12/16 +5/16
=17/16
=1 1/16
Use algebra to set up 2 equations.
Assign c as number of tickets for CATS and w for number of tickets of WICKED
c + w = 2700
c / w = 7 / 11
Then solve for one of them in the first equation
c = 2700 - w
Then put this value for c into the 2nd equation
(2700 - w) / w = 7 / 11
Now cross multiply the numerator by denominator of both numerator and denominator pairs
7w = 11 x (2700 - w)
7w = 29700 - 11w
Now solve for w
7w = 26700 - 11w
Add +11w to both sides
18w = 29700
Now divide by 18 on both sides
w = 1650
Then c is the remainder of that ... 2700 - 1650 = 1050
You can also check because 7 / 11 = 1050 / 1650
Answer:
The sum of the digit of the product is 13
Step-by-step explanation:
Given
Solving (a): The product
Solving (b): The sum of the digits
3/14 is 0.214 and 1/6 is 0.16
