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3 years ago

What unit of measurement would i use to measure a cereal box?

Mathematics

2 answers:

notsponge [240]3 years ago

6 0

You would use inches if you were in the United States. If you were not in the United States, you would use centimeters.

baherus [9]3 years ago

3 0

Probobly a ruler or one of those cups that has inches on them

You might be interested in

If r = 18 and t = 6, what is the value of the following expression?<br> r + 42 ÷ t · 5

AleksAgata [21]

Answer:

Step-by-step explanation:

42/6=7

7*5=35

18+35=53

4 0

3 years ago

Rectangle JKLM:J(-3, 8), K(-3,-1), L(4, -1),

Maslowich

Answer:

The perimeter of the Rectangle JKLM is 32 unit.

Step-by-step explanation:

Consider the provided coordinates.

Rectangle JKLM: J(-3, 8), K(-3,-1), L(4, -1), M(4,8)

First plot the points as shown in figure:

The required figure is shown below:

Now find the distance between JK by using the distance formula.

$d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$d=\sqrt{\left(-3-\left(-3\right)\right)^2+\left(-1-8\right)^2}=9$

Therefore, the length of JK is 9 unit.

Now find the length of the side JM

$d=\sqrt{\left(4-\left(-3\right)\right)^2+\left(8-8\right)^2}=7$

Therefore, the length of JM is 7 unit.

The perimeter of rectangle is: $P=2(l+b)$

Therefore,

$P=2(7+9)$

$P=2(16)$

$P=32$

Hence, the perimeter of the Rectangle JKLM is 32 unit.

4 0

4 years ago

Help pls this is for my math test.

ella [17]

Answer:

I think 1st option is correct

4 0

3 years ago

Read 2 more answers

What is the 4th term of the expanded binomial (2x – 3y)^6

san4es73 [151]

Answer:

The 4th term of the expanded binomial is $-4320x^3y^3$

Step-by-step explanation:

Considering:

$(x+y)^n = \sum_{k=0}^{n} \binom{n}{k} x^{n-k}y^k$

$(2x-3y)^6 = \sum_{k=0}^{6} \binom{6}{k} (2x)^{6-k}(-3y)^k$

Now, you gotta calculate for every value of $k$

$(2x-3y)^6 = \binom{6}{0} (2x)^{6-0}(-3y)^0 + \binom{6}{1} (2x)^{6-1}(-3y)^1 + \binom{6}{2} (2x)^{6-2}(-3y)^2 + \\$

$\binom{6}{3} (2x)^{6-3}(-3y)^3 + \binom{6}{4} (2x)^{6-4}(-3y)^4 + \binom{6}{5} (2x)^{6-5}(-3y)^5 + \binom{6}{6} (2x)^{6-6}(-3y)^6$

I will not write every product, but just solve following the steps:

For $k=0$

$\binom{6}{0} (2x)^{6-0}(-3y)^0$

$\frac{6!}{(6-0)!(0!)} (2x)^{6-0}(-3y)^0$

$\frac{6!}{6!} \left(2x\right)^{6-0}\cdot 1$

$1\cdot \:1\cdot \left(2x\right)^{6-0}$

$2^6x^6$

$64x^6$

$(2x-3y)^6=64x^6-576x^5y+2160x^4y^2-4320x^3y^3+4860x^2y^4-2916xy^5+729y^6$

8 0

3 years ago

Give the y intercept <br><br>y=3/2x+3

morpeh [17]

Answer:

Y intercept: (0,3) or 3

Step-by-step explanation:

the b in y = mx + b is the y intercept.

3 0

3 years ago