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mariarad [96]
3 years ago
14

The EXACT value of 2 divided (0.01)2

Mathematics
1 answer:
777dan777 [17]3 years ago
8 0

Answer:

Find the exact value using trigonometric identities.

100

Step-by-step explanation:

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I need some help please?
Leya [2.2K]

Answer:

38°

Step-by-step explanation:

hope this helps :)

4 0
2 years ago
In the document below it´s assigned a portion of the book, from there you need to choose a chapter, re-do the situation that the
Molodets [167]
What are you asking anyways hope you get a good grade
6 0
3 years ago
Read 2 more answers
What value of a satisfies the following equation?<br><br> -2(a + 3) = -4a + 32
Yanka [14]

Answer:

a = 19

Step-by-step explanation:

-2(a + 3) = -4a + 32

-2a - 6 = -4a +32

<u> +2a        +2a       </u>

-6 = -2a + 32

<u>-32         -32</u>

-38 = -2a

divide by -2

<u><em>a = 19</em></u>

5 0
2 years ago
Read 2 more answers
Help?,?,?,?.!.??.?.?.?.?.?.
DaniilM [7]

Answer:

Step-by-step explanation:

b(a + 1) + a = b*a + b + a = ab + b + a

1) b(2a +1 ) = b*2a + b*1 = 2ab + b  Not equivalent.

2)a + (a +1)*b = a + ab+ b     Equivalent

3) (a +1)(b+ a) = a*(b +a) + 1*(b+a) = ab+ a² +b + a  Not equivalent.

4) (a + 1)b + a = ab+ b + a   Equivalent

5) a + b(a+1) = a +ab + b Equivalent

6) a + (a +1) + b = a + a + 1 + b = 2a + 1 +b  Not equivalent.

7) a(b +1) + b = ab + a + b  Equivalent

5 0
3 years ago
The rectangle below has an area of 6n^4+20n^3+14n^26n 4 +20n 3 +14n 2 6, n, start superscript, 4, end superscript, plus, 20, n,
Sindrei [870]

Given:

Area of rectangle = 6n^4+20n^3+14n^2

Width of the rectangle is equal to the greatest common monomial factor of 6n^4, 20n^3,14n^2.

To find:

Length and width of the rectangle.

Solution:

Width of the rectangle is equal to the greatest common monomial factor of 6n^4, 20n^3,14n^2 is

6n^4=2\times 3\times n\times n\times n\times n

20n^3=2\times 2\times 5\times n\times n\times n

14n^2=2\times 7\times n\times n

Now,

GCF(6n^4, 20n^3,14n^2)=2\times n\times n=2n^2

So, width of the rectangle is 2n^2.

Area of rectangle is

Area=6n^4+20n^3+14n^2

Taking out GCF, we get

Area=2n^2(3n^2+10n+7)

We know that, area of a rectangle is the product of its length and width.

Since, width of the rectangle is 2n^2, therefore length of the rectangle is (3n^2+10n+7).

5 0
3 years ago
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