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Likurg_2 [28]
4 years ago
10

100÷50×(-3)-2×(-7)+14×(-2)÷7

Mathematics
1 answer:
Dmitrij [34]4 years ago
3 0

the answer is 4

use PEMDAS

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Answer a is 12/35 <br>answer b is 12/37 <br>answer c is 35/12 <br>answer d is 35/37​
Rainbow [258]

Answer:

c. 35/12

Step-by-step explanation:

Use soh cah toa, tangent equals opposite over adjecent. A also remember tangent by remembering that it is the only ratio to not use the hypotenuse.

7 0
3 years ago
How does the graph of
Effectus [21]

Answer:

Here we have:

f(x) = 2^x

g(x) = 0.5*2^(x - 3) - 1

We want to compare g(x) and f(x).

The first thing we should do here, is to define the transformations used.

Vertical translation:

For a function f(x), a vertical translation of N units is written as:

g(x) = f(x) + N

if N > 0, the translation is upwards

if N < 0, the translation is downwards.

Horizontal translation:

For a function f(x), a horizontal translation fo N units is written as:

g(x) = f(x + N)

if N > 0, the translation is to the left

if N < 0, the translation is to the right.

Vertical dilation:

For a general function f(x), a vertical dilation of scale factor k is written as:

g(x) = k*f(x).

Ok, now let's start with f(x), and try to use transformations to construct g(x).

We start with f(x).

If we start with a vertical dilation of scale factor k = 0.5, then:

g(x) = 0.5*f(x)

if now we apply a horizontal translation of 3 units to the right, we get:

g(x) = 0.5*f(x - 3)

if now we apply a vertical translation of 1 unit down, we get:

g(x) = 0.5*f(x - 3) - 1

Replacing by the actual function we get

g(x) = 0.5*2^(x - 3) - 1

So we got g(x).

Then, the graph of g(x) is the graph of f(x) dilated vertically by a scale factor of 0.5, then moved to the right 3 units, and then moved down one unit.

7 0
3 years ago
Need help, I cant simplify this
Kisachek [45]

Answer:

7^{\frac{2}{5}}

Step-by-step explanation:

Step 1: First apply radical rule in the given expression.

\sqrt[n]{a}=a^{\frac{1}{n}}

Here, \sqrt[3]{7}=7^{\frac{1}{3}}, \sqrt[5]{7}=7^{\frac{1}{5}}

The expression becomes \frac{\sqrt[3]{7}}{\sqrt[5]{7}}=\frac{7^{\frac{1}{3}}}{7^{\frac{1}{5}}}  

Step 2: Now, apply exponent rule in the above expression

\frac{x^{m}}{x^{n}}=x^{m-n}  

So, the expression becomes, 7^{\left(\frac{1}{3}-\frac{1}{5}\right)}.

Step 3: Take cross multiply the denominator and numerator of the fraction in the power of 7.

\Rightarrow 7^{\left(\frac{1}{3}-\frac{1}{5}\right)}=7^{\left(\frac{5-3}{15}\right)}=7^{\frac{2}{5}}

The answer is 7^{\frac{2}{5}}.

Hence the simplified form of \frac{\sqrt[3]{7}}{\sqrt[5]{7}}=7^{\frac{2}{5}}.

3 0
3 years ago
Solve A = h (a + b) for b.
fenix001 [56]

Answer:

b=A/h-a

Step-by-step explanation:

A=h(a+b)

a+b=A/h

b=A/h-a

8 0
3 years ago
What is the outlier in the following data : 85,83,9,85,82,81,90
kow [346]
It is 9 because all the other numbers are in the 80s and 90s 9 is way to low.
3 0
4 years ago
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