Question

Twenty pounds of a salt-water solution contains fifteen percent salt. How much salt is in the water?

Answer 1

Answer:

The salt is in the water be 3 lb.

Step-by-step explanation:

Formula

$Percentage = \frac{Part\ value\times 100}{Total\ value}$

As given

Twenty pounds of a salt-water solution contains fifteen percent salt.

Let us assume that the salt is in the water be x.

Percentage = 15%

Total value = 20 pounds

Put in the formula

$15= \frac{x\times 100}{20}$

$x = \frac{15\times 20}{100}$

$x = \frac{300}{100}$

x = 3 pounds

or

x = 3 lb

Therefore the salt is in the water be 3 lb.

Answer 2

It is 15% of 20 pound water
15/100x20
3lb