Twenty pounds of a salt-water solution contains fifteen percent salt. How much salt is in the water?
2 answers:
Answer:
The salt is in the water be 3 lb.
Step-by-step explanation:
Formula
As given
Twenty pounds of a salt-water solution contains fifteen percent salt.
Let us assume that the salt is in the water be x.
Percentage = 15%
Total value = 20 pounds
Put in the formula
x = 3 pounds
or
x = 3 lb
Therefore the salt is in the water be 3 lb.
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Answer:
Given : BRDG is a kite that is inscribed in a circle,
With BR = RD and BG = DG
To prove : RG is a diameter
Proof:
Since, RG is the major diagonal of the kite BRDG,
By the property of kite,
∠ RBG = ∠ RDG
Also, BRDG is a cyclic quadrilateral,
Therefore, By the property of cyclic quadrilateral,
∠ RBG + ∠ RDG = 180°
⇒ ∠ RBG + ∠ RBG = 180°
⇒ 2∠ RBG = 180°
⇒ ∠ RBG = 90°
⇒ ∠ RDG = 90°
Since, Angle subtended by a diameter or semicircle on any point of circle is right angle.
⇒ RG is the diameter of the circle.
Hence, proved.
