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riadik2000 [5.3K]
3 years ago
8

H. 539.28 - 6.42 Help pls

Mathematics
1 answer:
My name is Ann [436]3 years ago
6 0

Answer:

532.86

Step-by-step explanation:

just subtract starting with the numbers after the decimal place

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3(x+3)-5x simplify<br> Answer
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Answer: -2x + 9

First, Use the distributive property: 3(x+3)-5x       (3 multiplied by x is 3x and 3 multiplied by 3 is 9

Next, subtract the variable x: 3x+9-5x      (3x-5x=-2x

The answer is -2x+9

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Can someone please help me it’s urgent
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I believe it is 4 my good sir
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Simplify (7x2 - 2x + 9) + (3x2 + 15x – 4).
VikaD [51]

Hey! Your answer for this is

7x^2 + 3x^2 = 10x^2

-2x + 15x = 13x

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Hence, 10x^2 + 13x + 5.

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What is the answer is it a Yes or No HELP!!! This is at test and I only need help on this problem
allsm [11]

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Yes

Step-by-step explanation:

y is said to be a function of x. where x is the independent variable and y is the dependent variable. The height of the stacks is y and the number of cups in the stack is x, so yes, we can say that the height of the stack is a function of the number of cups in the stack.

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State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should
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Solving for <em>Angles</em>

\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A

* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

Solving for <em>Edges</em>

\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2

You would use this law under <em>two</em> conditions:

  • One angle and two edges defined, while trying to solve for the <em>third edge</em>
  • ALL three edges defined

* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:

  • Two angles and one edge defined, while trying to solve for the <em>second edge</em>
  • One angle and two edges defined, while trying to solve for the <em>second angle</em>
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* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0
2 years ago
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