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3 years ago

Can someone help me with this

Mathematics

2 answers:

frez [133]3 years ago

8 0

Answer:

8 laps

Step-by-step explanation:

Assuming in the equation given than n represents the number of laps run and t represents the time in minutes, when we plug in 16 in for t and simplify we get:

n=5/10*16

n=1/2*16 (Simplify the fraction by dividing top and bottom by 5)

n=16/2 (Multiply the fractions together by writing 16 as 16/1 and multiplying straight across)

n=8

Kipish [7]3 years ago

7 0

Answer:

Step-by-step explanation:

This question is a bit of a guess. You have to assume that n is in laps and that t is in minutes.

n = (5/10) * t Reduce 5/10 to 1/2

n = 1/2 * 16

n = 8

So if the assumptions are correct, he should be able to do 8 laps.

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4 years ago

Consider the function f(x) =2x-6 find f(2)

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Step-by-step explanation:

✧ $\underline{ \underline{ \large{ \tt{G \: I \: V \: E\: N}}} } :$

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3 years ago

In a test of the effectiveness of garlic for lowering cholesterol, 8181 subjects were treated with raw garlic. Cholesterol leve

xz_007 [3.2K]

Answer:

With garlic treatment, the mean change in LDL cholesterol is not greater than 0.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

In this case a paired t-test is used to determine the effectiveness of garlic for lowering cholesterol.

A random sample of 81 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment.

The hypothesis for the test can be defined as follows:

H₀: With garlic treatment, the mean change in LDL cholesterol is not greater than 0, i.e. d ≤ 0.

Hₐ: With garlic treatment, the mean change in LDL cholesterol is greater than 0, i.e. d > 0.

The information provided is:

$\bar d=0.40\\SD_{d}=16.2\\\alpha =0.01$

Compute the test statistic value as follows:

$t=\frac{\bar d}{SD_{d}/\sqrt{n}}\\\\=\frac{0.40}{16.2/\sqrt{81}}\\\\=0.22$

The test statistic value is 0.22.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

$p-value=P(t_{n-1}>0.22)\\=P(t_{80}>0.22)\\=0.4132$

*Use a t-table.

The p-value of the test is 0.4132.

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