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3 years ago

6

How to sketch the solutions to each. systems of inequalities

1 answer:

zloy xaker [14]3 years ago

4 0

It depends what inequality you have

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a baker used 660 boxes of cake mix to make a wedding cake. if each box called for 3 eggs, how many dozen eggs were used to make

yanalaym [24]

We know there’s 660 boxes and each box called for 3 eggs, therefore:

660=3X

when divide both sides by 3 to isolate the x, which will tell us the amount of eggs used…

660/3 = 220

6 0

2 years ago

Work out the circumference of this circle.

Ksenya-84 [330]

Formula for circumference of circle:
C=2πr
here radius, r=4 cm and π=3.142
Put values in formula.
C=2(3.142)(4)
C=25.1 cm (Rounded to 1 decimal place)

Answer: Circumference of the circle is 25.1 cm (Rounded to 1 decimal place)

6 0

3 years ago

Solve x - 20 > -15, and then graph the solutions. Use pencil and paper. Explain how

Artyom0805 [142]

Answer: x ≥ 6

Step-by-step explanation:

So 6 - 20 would equal -14 which is greater than -15 making it our inequality equal to or greater then 6

8 0

3 years ago

I need help please. It's trig

Olenka [21]

Answer:

6/10

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

one-third of the people from country A claim that they are from country B, and the rest admit they are from country A. One-fourt

In-s [12.5K]

Answer: 3 : 2

Step-by-step explanation:

Let A represents the total population of country A and B represents the total population of country B.

According to the question,

$\text{The population of country A that admit they are from B} = \frac{1}{3}\text{ of }A$

⇒ $\text{ The population of A that admit they are from country A }= A - \frac{1}{3} \text{ of } A$

$= \frac{3-1}{3} A$

$= \frac{2}{3} A$

$\text{The population of country B that admit they are from A} = \frac{1}{4}\text{ of }B$

⇒ $\text{ The total population that claims that they are from A }= \frac{2}{3} A +\frac{1}{4} B$

But, Again according to the question,

The total population that claims that they are from A = one half of the total population of A and B.

⇒ $\frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}(A+B)$

⇒ $\frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B$

⇒ $\frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B$

⇒ $\frac{2}{3} A - \frac{1}{2}A= \frac{1}{2}B-\frac{1}{4} B$

⇒ $\frac{4}{6} A - \frac{3}{6}A= \frac{2}{4}B-\frac{1}{4} B$

⇒ $\frac{1}{6} A = \frac{1}{4} B$

⇒ $A =\frac{6}{4}B$

⇒ $\frac{A}{B} =\frac{3}{2}$

8 0

3 years ago