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Igoryamba
3 years ago
15

Click on the graphic to match the equation with its correct graph. y=-x/2+1

Mathematics
1 answer:
tatuchka [14]3 years ago
8 0
There’s no graphs I could help you if you could take a picture of the graph
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Can someone tell me the y = mx + b<br> the answer to this. it’s slope intercept
skad [1K]

Answer:

It's y=3x

Step-by-step explanation:

The y-intercept is 0, it's direct variation. The slope(rise/run) is 3.

8 0
2 years ago
When Mei was born, her parents gave her 6 dolls
Marat540 [252]
Maybe 6+4x??? Not sure though
3 0
2 years ago
1. Find the surface area for the given prism. (11<br> 8 in.<br> 10 in.<br> 14 in,
DedPeter [7]

Answer:

SA = 664 square inches

Step-by-step explanation:

Surface area is the area of all the sides added together.  A prism has six sides.

Take the dimensions and change them so each of the numbers are multiplied with the others.

14 * 10 * 8

14 * 10 = 140

14 * 8 = 112

10 * 8 = 80

Multiply each answer by 2 because there are two sides that have the same dimensions.

14 * 10 = 140 * 2 = 280

14 * 8 = 112 * 2 = 224

10 * 8 = 80 * 2 = 160

Add the areas together.

280 + 224 + 160 = 664  

SA = 664 square inches

5 0
2 years ago
How do you graph y=12/x
Tpy6a [65]

Answer: \frac{12}{x} is an asymptote

Step-by-step explanation:

Apply a table, and plug in values of x into the equation.  For example f(2)=\frac{12}{2} =6. That's one of the points on the graph that we just found (2,6)

7 0
1 year ago
Find the equation of the line parallel to the line y = 4x – 2 that passes through the point (1, 5).
Lesechka [4]

Answer:

4x-y+1=0

Step-by-step explanation:

here,given equation of a line id

4x-y-2=0.. eqn(i)

equation of any line parallel to line (i) is

4x-y+k=0...eqn(ii)

since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]

4*1-5+k=0

or, 4-5+k=0

or,-1+k=0

•°•k=1

substituting the value of k=1 in eqn(ii),

4x-y+1=0 is the required equation of the line.

4 0
3 years ago
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