Answer:
96
Step-by-step explanation:
Total number of people attending the history museum is 200
Surveyed people are 25
Out of the 25, 12 people said yes
Therefore; the fraction which said yes = 12/25
To find the total number of people expected to say yes out of those that attended the history museum;
Fraction of the sampled that said yes × total number of people that attended.
= 12/25 × 200
= 96
You multiply 65 to the x and negative 5
Width of smaller tv=x. in feet
length of smaller tv =x+1
l of larger= x+1.5
w of larger = x +0.5
area = l x w
area = (x+1.5)(x+ 0.5)
area= x^2 +2x + 0.75
The spinner is not shown, so I will explain you the procedure with a spinner that is used in a problem with same statement, but different questions.
This explanation will suffice you even if the spinner is different, because you will know how to solve the problem.
The characteristics of the spinner are:
- circular board
- 8 congruent segments
- the segments are numbered 1, 2, 3, 4, 5, 6, 7, and 8
As conclusion, each segment (number) has the same change to be the outcome.
a) P (factor of 42). This is to find the probability that the outcome is a number that is factor of 42.
Then analyze the possible outcomes:
1: yes (1*42 = 42)
2: yes (2*21 = 42)
3: yes (3*14 = 42)
4: no
5: no
6: yes (6*7 = 42)
7: yes (7*6 = 42)
8 no.
Then five of the possibilities out of 8 are factor of 42, and P (factor of 42) = 5/8
Answer: 5/8
b) P (multiple of 6)
The only multiple of 6 in the numbers 1 through 8 is 6.
Then the P (multiple of 6) is 1/8
Answer: 1/8
The enclosure can be as large as 606 m2 in total.
Given that,
Let x be length of y be width of enclosure
fencing material cost $ 30 / m
Partition material cost $25/m
Total cost = (x+x+y+y)x 30+(y + y) x 25
c= 60(x+y) + 50y = 60 x + 110 y
4000 = 60 x + 110y
y = ( 400 - 6x / 11)
Now,Area of enclosure = x*y
A = x*(400 - 6x / 11)
A'(x)= 400-12x/11
for maximum area A'(x) = 0
400 - 12x/11 = 0,12x = 400,x = 100/3
A " ( x) = - 12/11 < 0 i.e., maximum
y = 400 - 6( 400/12 ) = 200/11 m
Maximum area = xy = 100/3 * 200/11 = 20000/33
=606.0606
A max = 606m²
Hence, the maximum area you can achieve for the enclosure is 606m²
Learn more about Area :
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