Answer:
Shifted 5 unit right side then stretched vertically by the factor 100
Step-by-step explanation:
Here, parent function,
Transformed function,
Since, if a function f(x) gives cf(x), where c is any number,
Then the function was vertically stretched by factor c,
While, the function gives f(x-c),
Then the function was shifted c unit right.
Hence, the graph of was shifted 5 unit right side then stretched vertically by the factor 100 to create the graph of 
Answer:
95% confidence interval for the difference between the average mass of eggs in small and large nest is between a lower limit of 0.81 and an upper limit of 2.39.
Step-by-step explanation:
Confidence interval is given by mean +/- margin of error (E)
Eggs from small nest
Sample size (n1) = 60
Mean = 37.2
Sample variance = 24.7
Eggs from large nest
Sample size (n2) = 159
Mean = 35.6
Sample variance = 39
Pooled variance = [(60-1)24.7 + (159-1)39] ÷ (60+159-2) = 7619.3 ÷ 217 = 35.11
Standard deviation = sqrt(pooled variance) = sqrt(35.11) = 5.93
Difference in mean = 37.2 - 35.6 = 1.6
Degree of freedom = n1+n2 - 2 = 60+159-2 = 217
Confidence level = 95%
Critical value (t) corresponding to 217 degrees of freedom and 95% confidence level is 1.97132
E = t×sd/√(n1+n2) = 1.97132×5.93/√219 = 0.79
Lower limit = mean - E = 1.6 - 0.79 = 0.81
Upper limit = mean + E = 1.6 + 0.79 = 2.39
95% confidence interval for the difference in average mass is (0.81, 2.39)
M=(y2-y1)/(x2-x1)
m=(-4-4)/(3-1)
m=-8/2
m=-4
so the answer should be first one
Answer:
right triangle
tep-by-step explanation:
i just took the test and worked this out
te sugiero que veas este video para que lo veas y cuando lo veas te explicara como hacerlo
