Ellen draws two plane figures.one of the figures has 3 more angles than the other figure.what shapes could she have drawn?

Joe works for a shipping company. He needs to figure out how many boxes will fit in the truck. First, he figures out the size of

disa [49]

Answer:

The answer is =A2*B2*C2

Step-by-step explanation:

3 0

3 years ago

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The coordinates of three vertices of square ABCD are A(−212,112),B(−212,−3), and C(2,112).

Lady_Fox [76]

Answer:

Step-by-step explanation:

Three of the coordinates of the square ABCD are A(-212,112) B(-212,-3) C(2,112). The image below shows the square is not ABCD but ABDC. In fact, this is not a square, as we'll prove later.

Note the x-coordinate of A and B are the same. It means this side is parallel to the y-axis. Also, the y-coordinate of A and C are the same, meaning this side is parallel to the x-axis. The missing point D should have the same x-coordinate as C and y-coordinate as B, i.e. D=(2,-3).

This shape has sides that are parallel to both axes.

To calculate the perimeter we find the length of two sides.

The distance from A to B is the difference between their y-axis:

w=112-(-3)=115

The distance from A to C is the difference between their x-axis:

l=2-(-212)=215

It's evident this is not a square but a rectangle. The perimeter is

P=2w+2l=330+430

P=760

7 0

3 years ago

-9 equals V over four

gogolik [260]

Answer:

-9=v/4

cross multiply

-9×4=v

-36=v

v=-36

7 0

3 years ago

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What is the rational number equivalent to 1 point 28 with a bar over 28? 1 and 6 over 97 1 and 28 over 99 1 and 8 over 33 1 and

katrin2010 [14]

In algebra, the conversion of a more complex number to a simpler mixed number is rather simple. For the repeated numbers, which are designated by the bar above them, we simply have to put over 9 for each number repeated and 0 for the non-repeated numbers.

In this item, we have 1.28 with bar above 28 signifying that the number can also be written as 1.28282828.... The mixed number is then equal to,
<em>1 and 28/99 or 1 and 28 over 99</em>

Therefore, the answer to this item is the second choice.

7 0

3 years ago

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1-cot^2a+cot^4a=sin^2a(1+cot^6a) prove it.

aliina [53]

Step-by-step explanation:

We have

1-cot²a + cot⁴a = sin²a(1+cot⁶a)

First, we can take a look at the right side. It expands to sin²a + cot⁶(a)sin²(a) = sin²a + cos⁶a/sin⁴a (this is the expanded right side) as cot(a) = cos(a)/sin(a), so cos⁶a = cos⁶a/sin⁶a. Therefore, it might be helpful to put everything in terms of sine and cosine to solve this.

We know 1 = sin²a+cos²a and cot(a) = cos(a)/sin(a), so we have

1-cot²a + cot⁴a = sin²a+cos²a-cos²a/sin²a + cos⁴a/sin⁴a

Next, we know that in the expanded right side, we have sin²a + something. We can use that to isolate the sin²a. The rest of the expanded right side has a denominator of sin⁴a, so we can make everything else have that denominator.

sin²a+cos²a-cos²a/sin²a + cos⁴a/sin⁴a

= sin²a + (cos²(a)sin⁴(a) - cos²(a)sin²(a) + cos⁴a)/sin⁴a

We can then factor cos²a out of the numerator

sin²a + (cos²(a)sin⁴(a) - cos²(a)sin²(a) + cos⁴a)/sin⁴a

= sin²a + cos²a (sin⁴a-sin²a+cos²a)/sin⁴a

Then, in the expanded right side, we can notice that the fraction has a numerator with only cos in it. We can therefore write sin⁴a in terms of cos (we don't want to write the sin²a term in terms of cos because it can easily add with cos²a to become 1, so we can hold that off for later) , so

sin²a = (1-cos²a)

sin⁴a = (1-cos²a)² = cos⁴a - 2cos²a + 1

sin²a + cos²a (sin⁴a-sin²a+cos²a)/sin⁴a

= sin²a + cos²a (cos⁴a-2cos²a+1-sin²a+cos²a)/sin⁴a

= sin²a + cos²a (cos⁴a-cos²a+1-sin²a)/sin⁴a

factor our the -cos²a-sin²a as -1(cos²a+sin²a) = -1(1) = -1

sin²a + cos²a (cos⁴a-cos²a+1-sin²a)/sin⁴a

= sin²a + cos²a (cos⁴a-1 + 1)/sin⁴a

= sin²a + cos⁶a/sin⁴a

= sin²a(1+cos⁶a/sin⁶a)

= sin²a(1+cot⁶a)

8 0

3 years ago