3 years ago

Find the magnitude and direction of the vector <3,9>

Mathematics

2 answers:

ser-zykov [4K]3 years ago

8 0

Answer:

Step-by-step explanation:

Yuliya22 [10]3 years ago

6 0

Answer:

9.49 units at an angle of 71.6° with the horizontal

Step-by-step explanation:

Magnitude: [x^2 + y^2]^(1/2)

(3^2 + 9^2)^(1/2)

(90)^(1/2) = 3root(10) = 9.49

Direction:

Angle with the horizontal: tan inverse (y/x)

tan inverse of (9/3)

tan inverse of 3 = 71.6°

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